Answer:



Step-by-step explanation:
Let 




We have the relation






1) 201.6 ounces. (16 ounces in 1 lb)
2) 3090 grams (1000g in 1 kg)
3)8820 in (36in in 1 yd)
PLEASE GIVE BRAINLIEST
Answer:
Step-by-step explanation:
22
Answer:
And if we solve for a we got
The 95th percentile of the hip breadth of adult men is 16.2 inches.
Step-by-step explanation:
Let X the random variable that represent the hips breadths of a population, and for this case we know the distribution for X is given by:
Where
and
For this part we want to find a value a, such that we satisfy this condition:
(a)
(b)
We can find a quantile in the normal standard distribution who accumulates 0.95 of the area on the left and 0.05 of the area on the right it's z=1.64
Using this value we can set up the following equation:
And we have:
And if we solve for a we got
The 95th percentile of the hip breadth of adult men is 16.2 inches.
X= 5x Y=-6 I just added them together