Write the equation of a line that passes through (3.5,0) and is perpendicular to 8y+4x=64.
1 answer:
Answer:
y = 2x + 3.5
Step-by-step explanation:
Step 1: find the slope
8y + 4x = 64
8y = 64 - 4x
Make y the subject of the formula
y = (64 - 4x)/8
y = ( -4x + 64)/8
Separate to get slope
y = -4x/8 + 64/8
y = -x/2 + 8
Slope is the coefficient of x
m = -1/2
Note: if two lines are perpendicular to the other , it is negative reciprocal to each other
m = 2
Using the point slope form equation
y - y1 = m(x - x1)
y - y1 = 2(x - x1)
Substitute the point
( 3.5 , 0)
x1 = 3.5
y1 = 0
y - 3.5 = 2( x - 0)
open the bracket
y - 3.5 = 2x - 0
y = 2x - 0 + 3.5
y = 2x + 3.5
The equation of the line is
y = 2x + 3.5
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