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3 years ago

It’s has to be in y=Mx+b that you

Mathematics

1 answer:

Fudgin [204]3 years ago

7 0

Answer:

try this

Step-by-step explanation:

desmos graphing will give u answers

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PLEASE HELP, ILL GIVE YOU 20 POINTS!!!

Troyanec [42]

Answer:

-2,4

Step-by-step explanation:

i think

5 0

4 years ago

Read 2 more answers

If 3a=27, what is the value of 6a+3?

Luba_88 [7]

57 because 3 times 9 equals 27

7 0

3 years ago

Mrs. kirby, 58, is a moderately active woman. she works in the garden almost daily, occasionally walks with her friends, and bab

uranmaximum [27]

Answer:

61,01%

Step-by-step explanation:

We must consider that her total energy intake is the addition of the energy given by the carbohydrates, fats and proteins she takes.

1g of carbohydrates contains 4kcal

1g of proteins contains 4kcal

1g of fat contains 9 kcal.

That is: 243 g of carbohidrates is equal to 972 kcal; 41g of fat is equal to 369 kcal and 63 g of proteins is equal to 252 kcal.

If we sum up all the calories she intakes in one day, the result is= 972kcal+369kcal+252kcal=1593kcal.

Now, we make a rule of 3: If 1593kcal is the 100% of the intake, then 972kcal = 972kcal*100%/1593kcal = 61,01%

5 0

3 years ago

Ten college students were randomly selected. Their grade point averages (GPAs) when they entered the program were between 3.5 a

solong [7]

Answer:

The 95% confidence interval for the true slope is (0.03985, 0.14206).

Step-by-step explanation:

For the regression equation:

$\hat y=\alpha +\hat \beta x$

The (1 - <em>α</em>)% confidence interval for the regression coefficient or slope $(\hat \beta )$ is:

$Ci=\hat \beta \pm t_{\alpha/2, (n-2)}\times SE(\hat \beta )$

The regression equation for current GPA (Y) of students based on their GPA's when entering the program (X) is:

$\hat Y=3.584756+0.090953 X$

The summary of the regression analysis is:

Predictor Coefficient SE t-stat p-value

Constant 3.584756 0.078183 45.85075 5.66 x 10⁻¹¹

Entering GPA 0.090953 0.022162 4.103932 0.003419

The regression coefficient and standard error are:

$\hat \beta = 0.090953\\SE (\hat \beta)=0.022162$

The critical value of <em>t</em> for 95% confidence level and 8 degrees of freedom is:

$t_{\alpha/2, n-2}=t_{0.05/2, 10-2}=t_{0.025, 8}=2.306$

Compute the 95% confidence interval for $(\hat \beta )$ as follows:

$CI=\hat \beta \pm t_{\alpha/2, (n-2)}\times SE(\hat \beta )\\=0.090953\pm 2.306\times 0.022162\\=0.090953\pm 0.051105572\\=(0.039847428, 0.142058572)\\\approx (0.03985, 0.14206)$

Thus, the 95% confidence interval for the true slope is (0.03985, 0.14206).

6 0

3 years ago

Write the equation of the line perpendicular to y= 2/5x+6/6 that passes through the point (-2,6)

Oliga [24]

The line to find: y = mx + b
the line perpendicular to y= 2/5x+6/6 so it has the slope m × 2/5 = -1
thus the slope m = -5/2
the line passes through the point (-2,6) so:
6 = (-5/2)×(-2) + b so b = 1

the equation of the line is y = -5/2x +1

3 0

4 years ago