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Kay [80]
2 years ago
6

It’s has to be in y=Mx+b that you

Mathematics
1 answer:
Fudgin [204]2 years ago
7 0

Answer:

try this

Step-by-step explanation:

desmos graphing will give u answers

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Kristen just deposited $6,500 into a new bank account that pays 4.5% interest the first year and 3% compounded annually each yea
vladimir2022 [97]

This question is about compound interest, but since the interest is such a small number you can use what you know about simple interest to eliminate some answers.

You can immediately eliminate choice A as a clunker, since it is less than the original amount in the account.

Consider what the amount of interest would be if you make the rate much larger than the original rate, say 10%, or 0.1:

$6,500 × 0.1 = $650

If this amount were added to the original amount each year for two years, the total would be:

$6,500 + $650 + $650 = $6,500 + $1,300 = $7,800

This is an over-estimate for the information given, and since choices C and D are even greater than this over-estimate, they can be eliminated. That means choice B is the correct answer.

6 0
2 years ago
Read 2 more answers
Segments
Ipatiy [6.2K]

There are several ways two triangles can be congruent.

  • \mathbf{AC = BD}<em> congruent by SAS</em>
  • \mathbf{\angle ABC \cong \angle BAD}<em> congruent by corresponding theorem</em>

In \mathbf{\triangle AOL} and \mathbf{\triangle BOK} (see attachment), we have the following observations

1.\ \mathbf{AO = DO} --- Because O is the midpoint of line segment AD

2.\ \mathbf{BO = CO} --- Because O is the midpoint of line segment BC

3.\ \mathbf{\angle AOB =\angle COD} ---- Because vertical angles are congruent

4.\ \mathbf{\angle AOC =\angle BOD} ---- Because vertical angles are congruent

Using the SAS (<em>side-angle-side</em>) postulate, we have:

\mathbf{AC = BD}

Using corresponding theorem,

\mathbf{\angle ABC \cong \angle BAD} ---- i.e. both triangles are congruent

The above congruence equation is true because:

  1. <em>2 sides of both triangles are congruent</em>
  2. <em>1 angle each of both triangles is equal</em>
  3. <em>Corresponding angles are equal</em>

See attachment

Read more about congruence triangles at:

brainly.com/question/20517835

3 0
2 years ago
A) Draw the graph of y= 4x - 1 on the grid
UkoKoshka [18]

9514 1404 393

Answer:

  see attached for a graph

  x = 0.5 when y = 1

Step-by-step explanation:

The graph has a y-intercept of -1, which is halfway between 0 and -2. It goes up 4 units (2 vertical grid spaces) for 1 unit to the right (1 horizontal grid space). It seems to cross y = 1 at about x = 1/2.

x = 1/2 when y = 1.

4 0
2 years ago
Carly takes three steps to walk the same distance as jim walks in four steps. each of carly’s steps covers 0. 5 metres. how many
myrzilka [38]

The distance travelled by Jim in 24 step is 9 miles by unitary method.

According to the given question.

The number of steps travelled by Jim = 24

Also, it is given that "Carly takes three steps to walk the same distance as Jim walks in four steps".

Therefore, by unitary mehod we can say that

The number of steps walked by Carly = 3 × (24/4) = 3 × 6  = 18

So, the distance travelled by Carly in 18 steps

= 18 × 0.5miles

= 9 miles

Since, the Carly's 18 steps is equals to Jim's 24 steps.

Therefore, the distance travelled by Jim in 24 step is 9 miles.

Find out more information about unitary method here:

brainly.com/question/22056199

#SPJ4

5 0
1 year ago
Suppose the rate of type II diabetes in 40- to 59-year-olds is 7% among Caucasians, 10% among African-Americans, 12% among Hispa
melomori [17]

Answer:

The overall probability of type II diabetes among 40- to 59-year-olds in Houston is 9.3%.

Step-by-step explanation:

We have these following rates of type II diabetes:

7% among Caucasians

10% among African-Americans

12% among Hispanics

5% among Asian-Americans.

The ethnic distribution of Houston is:

30% Caucasian

25% African-American

40% Hispanic

5% Asian-American

What is the overall probability of type II diabetes among 40- to 59-year-olds in Houston?

P = P_{1} + P_{2} + P_{3} + P_{4}

P_{1} is the probability of finding a Caucasian with type II diabetes in Houston. So it is 7% of 30%.

P_{1} = 0.07*0.30 = 0.021

P_{2} is the probability of finding an African-American with type II diabetes in Houston. So it is 10% of 25%.

P_{2} = 0.1*0.25 = 0.0215

P_{3} is the probability of finding a Hispanic with type II diabetes in Houston. So it is 12% of 40%.

P_{3} = 0.12*0.40 = 0.048

P_{4} is the probability of finding an Asian-American with type II diabetes in Houston. So it is 5% of 5%.

P_{3} = 0.05*0.05 = 0.0025

P = P_{1} + P_{2} + P_{3} + P_{4} = 0.021 + 0.0215 + 0.048 + 0.0025 = 0.093

The overall probability of type II diabetes among 40- to 59-year-olds in Houston is 9.3%.

4 0
3 years ago
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