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TEA [102]
4 years ago
15

I dont understand 5a can u please help?

Mathematics
1 answer:
tankabanditka [31]4 years ago
6 0
___ ___
CDE ECD

i think thats what it is
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2x + y = 3
Arlecino [84]
It’s d
You just have to keep on substitutes x or y . I added a picture hope that helps

3 0
3 years ago
The Mapleton Middle School band has 41 students. Six students play a percussion instrument. What percent of students in the band
Sedaia [141]

Answer:

the  percentage of the students in the band that play a percussion instrument is 14.6%

Step-by-step explanation:

The computation of the percentage of the students in the band that play a percussion instrument is as followS;

= number of students played percussion instrument ÷ total number of students

= 6 students ÷ 41 students

= 14.6%

Hence, the  percentage of the students in the band that play a percussion instrument is 14.6%

The same is relevant

3 0
3 years ago
Converting from vertex to standard form <br><br>plzz help ;( ​
Trava [24]

Answer:

x²-4x+7

-x²-6x-12

Step-by-step explanation:

1.) the first thing we do is expand the exponent (or mulitply  (x-2)(x-2) the images below will show you how to do that

We get x²-4x+4 and then just need to add three

x²-4x+7

2.)

We do the same thing (expand the exponent) and get x²+6x+9

which means so far we have

-(x²+6x+9)-3

carry out the negative sign and subtract 3

-x²-6x-12

5 0
3 years ago
Can anyone help me please? Also explain if you can. Thank you :)
djverab [1.8K]
The answer is 6/9 or 2/3 because 2X2X2=8 and 9X9X9=729......it equals 8/729 






3 0
3 years ago
Find the volume V of the solid obtained by rotating the region bounded by the given curves about the specified line. Y = (4/9) x
frez [133]

Answer:

V = 8.06 cubed units

Step-by-step explanation:

You have the following curves:

y_1=\frac{4}{9}x^2=f(x)\\\\y_2=\frac{13}{9}-x^2=g(x)

In order to calculate the solid of revolution bounded by the previous curves and the x axis, you use the following formula:

V=\pi \int_a^b [(g(x))^2-(f(x))^2]dx       (1)

To determine the limits of the integral you equal both curves f=g and solve for x:

f(x)=g(x)\\\\\frac{4}{9}x^2=\frac{13}{9}-x^2\\\\\frac{4}{9}x^2+x^2=\frac{13}{9}\\\\\frac{13}{9}x^2=\frac{13}{9}\\\\x=\pm 1

Then, the limits are a = -1 and b = 1

You replace f(x), g(x), a and b in the equation (1):

V=\pi \int_{-1}^{1}[(\frac{13}{9}-x^2)^2-(\frac{4}{9}x^2)^2]dx\\\\V=\pi \int_{-1}^1[\frac{169}{81}-\frac{26}{9}x^2+x^4-\frac{16}{81}x^4]dx\\\\V=\pi \int_{-1}^1 [\frac{169}{81}-\frac{26}{9}x^2+\frac{65}{81}x^4]dx\\\\V=\pi [\frac{169}{81}x-\frac{26}{27}x^3+\frac{65}{405}x^5]_{-1}^1\\\\V\approx8.06\ cubed\ units

The volume of the solid of revolution is approximately 8.06 cubed units

8 0
4 years ago
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