Answer:A
Step-by-step explanation: the diagonals face each other making them perpendicular making both sides parallel to each other, being straight.
For

to be continuous at

, you need to have the limit from either side as

to be the same.


If

and

, then the limit from the right would be

, so the answer to part (1) is no, the function would not be continuous under those conditions.
This basically answers part (2). For the function to be continuous, you need to satisfy the relation

.
Part (c) is done similarly to part (1). This time, you need to limits from either side as

to match. You have


So,

and

have to satisfy the relation

, or

.
Part (4) is done by solving the system of equations above for

and

. I'll leave that to you, as well as part (5) since that's just drawing your findings.
Answer:5 there is no and
6 is not definite
7 yes
Step-by-step explanation:in 6 they can't multiply
7 they are lnverses
For quadratics, these formulas are used mainly for factoring.
Your equation can be written as ...
... 2(x² +2x -3) = 0
You factor this by looking for factors of -3 (c=x1·x2) that add to give +2 (b=-(x1+x2)). These are {-1, +3}, so the factorization is ...
... 2(x -1)(x +3) = 0
The roots are then 1 and -3, which sum to -b = -2.
(You will note that the numbers used in the binomial factors are the opposites of the roots x1 and x2 in the Viete's Formulas. That is how we can look for them to sum to "b", rather than "-b".)