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alukav5142 [94]
3 years ago
13

Jillian’s school is selling tickets for a play. The tickets cost $10.50 for adults and $3.75 for students. The ticket sales for

opening night totaled $2071.50. The equation 10.50 a plus 3.75 b equals 2071.50, where a is the number of adult tickets sold and b is the number of student tickets sold, can be used to find the number of adult and student tickets. If 82 students attended, how may adult tickets were sold? Answer: 168 adult tickets
Mathematics
2 answers:
Sever21 [200]3 years ago
8 0

Answer:

Step-by-step explanation:

10.5a + 3.75b = 2071.50

b = 82 students

Substitute 'b' value in the equation

10.5a + 3.75 * 82 = 2071.50

10.5a + 307.5 = 2071.50

10.5a = 2071.50 - 307.5

10.5a = 1764

Divide both sides by 10.5

a = 1764/10.5

a =17640/105

a= 168

168 adult tickets were sold

Digiron [165]3 years ago
3 0
The absurdity
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#1 - HINT - you are finding the total amount make sure you add the interest you calculate to the original deposit amount
Andreyy89

Answer:

$292.50

Step-by-step explanation:

Equation - A = P(1 + rt)

Calculation:

First, converting R percent to r a decimal

r = R/100 = 2.5%/100 = 0.025 per year.

Solving our equation:

A = 260(1 + (0.025 × 5)) = 292.5

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The total amount accrued, principal plus interest, from simple interest on a principal of $260.00 at a rate of 2.5% per year for 5 years is $292.50.

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11.1.21 A survey​ asked, "How many tattoos do you currently have on your​ body?" Of the males​ surveyed, responded that they had
hram777 [196]

Complete question :

The Harris Poll conducted a survey in which they asked, "How many tattoos do you currently have on your body?" Of the 1205 males surveyed, 181 responded that they had at least one tattoo. Of the 1097 females surveyed, 143 responded that they had at least one tattoo. Construct a 95% confidence interval to judge whether the proportion of males that have at least one tattoo differs significantly from the proportion of females that have at least one tattoo. Interpret the interval.

Answer:

(−0.0085 ; 0.0481)

Step-by-step explanation:

Given that :

n1 = 1205 ; x1 = 181 ; n2 = 1097 ; x2 = 143 ; α = 95%

Zα/2 = 1.96 ( Z table)

Confidence interval : (p1 - p2) ± E

E =Zα/2 * √[(p1q1/n1) + (p2q2/n2)]

p1 = x1 /n1 =181/1205 = 0.1502

q1 = 1 - p1 = 1 -0.1502 = 0.8498

p2 = x2/n2 = 143/1097 = 0.1304

q2 = 1 - p2 = 1 -0.1304 = 0.8696

E = 1.96 * √(0.0001059 + 0.0001033)

E = 0.0283

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Upper boundary = 0.0198 + 0.0283 = 0.0481

(−0.0085 ; 0.0481)

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