Answer:
They should in crease budget.
Step-by-step explanation:
divide each number by 2 to see how often they go equally/use the data table you have available of the two climbers.
Answer:

Step-by-step explanation:
Given

Required
Find

Calculate 
Using tan rule

So:






'
'So:



Answer:
61 degrees
Step-by-step explanation:
A right angle equals 90 degrees.
90-29= 61
(-$11) x 12. That would be the equation because there are 12 months, so you would multiply -11 from 12 to get -132 every year for the tennis club membership.