$\bf \textit{volume of a sphere}\\\\ V=\cfrac{4\pi r^3}{3}~~ \begin{cases} r=radius\\[-0.5em] \hrulefill\\ V=1767.1 \end{cases}\implies 1767.1=\cfrac{4\pi r^3}{3}\implies 5301.3=4\pi r^3 \\\\\\ \cfrac{5301.3}{4\pi }=r^3\implies \sqrt[3]{\cfrac{5301.3}{4\pi }}=r\implies 7.4999\approx r$

3 0

2 years ago

Can someone help me do these it’s really hard

Elena L [17]

Answer:

40 cubes

Step-by-step explanation:

multiply side lengths or the prism by 2, then solve for volume

2.5 * 2 = 5

2 * 2 = 4

1 * 2 = 2

5 * 4 * 2 = 40

4 0

2 years ago

-3. 12=2+<br><img src="https://tex.z-dn.net/?f=%20%5Cfrac%7Bx%7D%7B2%7D%20" id="TexFormula1" title=" \frac{x}{2} " alt=" \frac{x

Kipish [7]

Which one has the variable?

4 0

2 years ago