Complete question is;
Suppose that a dimension x and the area A = 2x² of a shape are differentiable functions of t. Write an equation that relates dA/dt to dx/dt.
Answer:
Step-by-step explanation:
Since A = 2x²
Let's differentiate both sides with respect to x.
dA/dx = 4x
Now, we want to find the relationship between dA/dt and dx/dt
dA/dt can be expressed as;
(dA/dt) = (dA/dx) × (dx/dt)
Thus;
dA/dt = 4x(dx/dt)
Thus, the equation that relates dA/dt to dx/dt is;
dA/dt = 4x(dx/dt)
Answer:
it is c because i took the test yes it is
Step-by-step explanation:
Okay, so I'm almost positive the slope is m=1/1. I know this because the line rises one and runs one.
Answer:
219 over 1000
Step-by-step explanation:
Answer:
Area = 245 ft
(Width
Step-by-step explanation:
l = 5w
Where l is length and w is width.
We also know that the perimeter is 84 ft, so:
2l + 2w = 84
Now we can plug in 5w for l since we found the equality earlier:
2(5w) + 2w = 84
and then solve for w:
10w + 2w = 84
12w = 84
w = 7
so
l = 5 × 7
l = 35
The length is 35 and width is 7 so
the area of the rectangle is
