Answer:
A i think
Step-by-step explanation:
Answer:
Step-by-step explanation:
Answer:
The width of the art projects of area 63.6 square inches is 7.97 inches .
Step-by-step explanation:
Given as :
The area of the square art project = 63.6 square inches
Since The shape of the art project is square
So, The Area of square = A = side × side = side²
Now, let the measure of the width of art project = w inches
I.e side = w inches
or , A = side²
Or , A = w²
Or, 63.6 = w²
So, w = 
I.e w = 7.97 inches
So, the width of the projects = w = 7.97 inches
Hence The width of the art projects of area 63.6 square inches is 7.97 inches . Answer
Let the side length of the original square be x, then
1/4 x^2 = (x - 3)^2
x^2 = 4(x^2 - 6x + 9) = 4x^2 - 24x + 36
3x^2 - 24x + 36 = 0
3(x^2 - 8x + 12) = 0
x^2 - 8x + 12 = 0
x^2 - 2x - 6x + 12 = 0
x(x - 2) - 6(x - 2) = 0
(x - 6)(x - 2) = 0
x - 6 = 0 or x - 2 = 0
x = 6 or x = 2
therefore, the side length of the original square is 6 inches.
Hope this helps!
What? explain or show a picture of the problem:/