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ASHA 777 [7]
3 years ago
6

Which describes the graph of fx=[x]-2 on [0, 3)?

Mathematics
1 answer:
marissa [1.9K]3 years ago
8 0

Answer:

Step-by-step explanation:

Find the absolute value vertex. In this case, the vertex for  

y = |x − 2 | + 1 is  ( 2 , 1 ) .

To find the  x  coordinate of the vertex, set the inside of the absolute value  

x − 2  equal to  0 . In this case,  

x − 2 = 0. x−2 = 0

Add  2  to both sides of the equation.

x = 2

Replace the variable  x  with  2  in the expression.

y = | ( 2 ) − 2 | + 1

Simplify  

| ( 2 ) − 2 | + 1 .

Simplify each term.

Subtract  2  from  2

y = | 0 | + 1

The absolute value is the distance between a number and zero. The distance between  0  and  0  is  0 .

y = 0 + 1

Add  0  and  1 .

y = 1

The absolute value vertex is  ( 2 , 1 ) . ( 2 , 1 )

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Answer:

  smallest: 8x -3 = 4; 1y +9 = 2. total = -49/8

  largest: 1x -9 = 8; 2y +3 = 7. total = 19

Step-by-step explanation:

If we use variables to represent the box contents, we can write ...

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Then the values of x and y are ...

  x = (c +b)/a

  y = (f -e)/d

For positive integer values of the variables, x will always be positive, and y may or may not be negative.

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For the sum to be the smallest, we must have x be as small as possible and the ratio (f-e)/d be as negative as possible.

x will be small for large 'a' and for (c+b) small. For y to be as negative as possible, we want 'd' and 'f' small and 'e' large. Best results are obtained for

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For these coefficients, the sum is -6 1/8 = -49/8.

(note that the values of 'b' and 'c' can be swapped with no net effect)

<h3>Largest sum</h3>

For the sum to be the largest, we must have x as large as possible: (b+c) large and 'a' small. At the same time we must have y be positive and as large as possible: (f-e) positive and large, 'd' small. Best results are obtained for

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For these coefficients, the sum is 19. Again, 'b' and 'c' can be swapped with no effect.

_____

<em>Additional comment</em>

These extreme values are verified by examination of the 60,480 possible permutations of the coefficients.

8 0
3 years ago
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lara31 [8.8K]

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AD (common)

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Angle CAD = Angle BAD (angle on the circumference is half the angle at the centre)

Therefore, ABD and DCA are congruent by SAS postulate

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Answer:

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Step-by-step explanation:

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