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3 years ago

Gambling at a slot machine is an example of which reinforcement schedule?

Mathematics

1 answer:

gogolik [260]3 years ago

8 0

Answer:

d. Variable ratio

Step-by-step explanation:

We are asked to determine that gambling at a slot machine is an example of which reinforcement schedule.

Let us see our given choices one by one.

a. Fixed ratio

We know that in fixed ratio schedule, reinforcement is delivered after the completion of a number of responses. An example of fixed ratio is a reward to every 6th response.

b. Fixed interval

We know that in fixed interval schedule the first response is rewarded only after a specified amount of time has elapsed. An example of fixed interval schedule is weekly paycheck.

c. Variable interval

We know that in variable interval schedule, the reinforcement is delivered at changing and unpredictable intervals of time.

d. Variable ratio

In variable ratio schedule, a response is reinforced after an unpredictable number of responses. Gambling and lottery are examples of variable ratio.

Therefore, option 'd' is the correct choice.

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If we inscribe a circle such that it is touching all six corners of a regular hexagon of side 10 inches, what is the area of the

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Answer:

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<h3>Area of the Inscribed Hexagon</h3>

Refer to the first diagram attached. This inscribed regular hexagon can be split into six equilateral triangles. The length of each side of these triangle will be $10$ inches (same as the length of each side of the regular hexagon.)

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$\displaystyle 10\, \sin\left(60^\circ\right) = 10 \times \frac{\sqrt{3}}{2} = 5\sqrt{3}$ .

The area (in square inches) of this equilateral triangle will be:

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Note that the inscribed hexagon in this question is made up of six equilateral triangles like this one. Therefore, the area (in square inches) of this hexagon will be:

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<h3>Area of of the circle that is not covered</h3>

Refer to the first diagram. The length of each side of these equilateral triangles is the same as the radius of the circle. Since the length of one such side is $10$ inches, the radius of this circle will also be $10$ inches.

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$\begin{aligned}&\text{Area of circle} - \text{Area of hexagon} \\ &= 100\pi - 150\sqrt{3}\end{aligned}$ .

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