Okay, so for the second paper thing, it's B and F (the second one and the last one)
That's all I really know! I'm taking Alg. 1 right now XD
Good luck!
Y = 16x^2 + 36
Lets find the intercepts, making x and y to zero and solving:
<span>0 = 16x^2 + 36
</span><span>16x^2 = -36
</span>therefore there is not x-intercept, that is, when y equals zero the function does not have a value, is not defined.
Now, the y intercept, that is when x equals zero:
<span>y = 16x^2 + 36
</span><span>y = 16(0)^2 + 36
</span>y = 36
so, when x = 0, y = 36, that is, the function hits the y axis when x = 0
Answer: 9/2, 4.5
Step-by-step explanation:
It’s c just to let you know I have done this before
Answer:
not enough information
Step-by-step explanation:
Perpendicular lines intersect at right angles. Since lines c and b are perpendicular, angles 1, 2, 3, and 4 are right angles, and each one measures 90 degrees.
Angle 2 is formed by the intersection of lines a and b. We are not told anything about the intersection of lines a and b, and we are not told anything about the relationship between lines a and c, so we do not have enough information to determine the measure of angle 2.
