T1=S/V1T2=Ttot-T1=(2S/Vtot)-S/V1V2=S/T2 = S / (2S/Vtot-S/V1)Simplify in V2 = V1Vtot/(2V1-Vtot) = 48 * 90 / 6 = 720 km/hr
Answer:
0.00321 Nm
Explanation:
= Final angular velocity = 3.5 rad/s
= Initial angular velocity = 0
= Angular acceleration
= Angle of rotation = 2 rev
Equation of rotational motion
![\omega_f^2-\omega_i^2=2\alpha \theta\\\Rightarrow \alpha=\frac{\omega_f^2-\omega_i^2}{2\theta}\\\Rightarrow \alpha=\frac{3.5^2-0^2}{2\times 2\pi \times 1.8}\\\Rightarrow \alpha=0.54156\ rad/s^2](https://tex.z-dn.net/?f=%5Comega_f%5E2-%5Comega_i%5E2%3D2%5Calpha%20%5Ctheta%5C%5C%5CRightarrow%20%5Calpha%3D%5Cfrac%7B%5Comega_f%5E2-%5Comega_i%5E2%7D%7B2%5Ctheta%7D%5C%5C%5CRightarrow%20%5Calpha%3D%5Cfrac%7B3.5%5E2-0%5E2%7D%7B2%5Ctimes%202%5Cpi%20%5Ctimes%201.8%7D%5C%5C%5CRightarrow%20%5Calpha%3D0.54156%5C%20rad%2Fs%5E2)
Moment of inertia is given by
![I=mr^2\\\Rightarrow I=0.25\times 0.154^2\\\Rightarrow I=0.005929\ kgm^2](https://tex.z-dn.net/?f=I%3Dmr%5E2%5C%5C%5CRightarrow%20I%3D0.25%5Ctimes%200.154%5E2%5C%5C%5CRightarrow%20I%3D0.005929%5C%20kgm%5E2)
Torque is given by
![\tau=I\alpha\\\Rightarrow \tau=0.005929\times 0.54156\\\Rightarrow \tau=0.00321\ Nm](https://tex.z-dn.net/?f=%5Ctau%3DI%5Calpha%5C%5C%5CRightarrow%20%5Ctau%3D0.005929%5Ctimes%200.54156%5C%5C%5CRightarrow%20%5Ctau%3D0.00321%5C%20Nm)
The torque required is 0.00321 Nm
Answer:
The wavelength of WFNX’s radio waves with the given speed and frequency is 2.95m.
Given data in the question;
Speed of wave;
Frequency of wave;
wavelength;
To determine the wavelength of the radio wave, we use the expression for the relations between wavelength, frequency and speed.
Where is wavelength, f is frequency and c is the speed.
We substitute our given values into the equation
Therefore, the wavelength of WFNX’s radio waves with the given speed and frequency is 2.95m.
Explanation:
Simple, A. None of the other answers make sense so, A.
v
Convert the given temperatures from celsius to kelvin since we are dealing with gas.
To convert to kelvin, add 273.15 to the temperature in celsius.
T1 = 22 + 273.15 = 295.15 k
T2 = 4 + 273.15 = 277.15 k
V1 = 0.5 L
Let's find the final volume (V2).
To solve for V2 apply Charles Law formula below: