The answer is electric potential difference
Answer:
The acceleration of the cart is 283.54g
Explanation:
It is given that,
Initial speed of the car, u = 35 km/h = 9.72 m/s
Finally, it stops, v = 0
Diameter of the dime, d = 1.7 cm
Let a is the acceleration of the car. Using third equation of motion to find it as :





So, the acceleration of the car is
and it is decelerating.
Since, 
So, 
So, the acceleration of the cart is 283.54g. Hence, this is the required solution.
Answer:
amount of work done is
Explanation:
Formula for work done by force field

where
r(t) is parametrization of line
as it is straight line so

thus,
r(t) = (1-t)(-1,1) + t(3,-3)
= (-1+t,1-t) + (3t - 3t)
= (-1+t +3t, 1-t-3t)
r(t) = (4t -1, 1- 4t)
r'(t) = (4,-4)
putting value in above integral


![= 4[ -16 \frac{t^3}{3} + 16\frac{t^2}{2} - 3t]_{0}^{1}](https://tex.z-dn.net/?f=%3D%204%5B%20-16%20%5Cfrac%7Bt%5E3%7D%7B3%7D%20%2B%2016%5Cfrac%7Bt%5E2%7D%7B2%7D%20-%203t%5D_%7B0%7D%5E%7B1%7D)
Answer:
53.5 N
Explanation:
Vertical component of the F force 50 sin30 = 25 N upward
force of gravity = m g = 8 * 9.81 =78.5 N Downward
NET downward force by block on table = net upward force exerted by table = 78.5 -25 =53.5 N