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kupik [55]
3 years ago
15

The train 'A' travelled a distance is f 120 km in 3 hours , Whereas another train 'B' travelled a distance of 180 km in 4 hours

. Which train tracelled faster
Physics
2 answers:
Radda [10]3 years ago
6 0

Answer:

B train!

Explanation:

A train travelled at 40 km/hr. (120/3)

B train traveled at 45 km/hr (180/4)

Mama L [17]3 years ago
5 0

Answer:

Train B

Explanation:

Let's find each train's speed using the following formula.

s=\frac{d}{t}

where d is distance and t is time.

<u>Train A</u>

Train A travelled a distance of 120 kilometers in 3 hours.

s=\frac{d}{t}\\d=120 km\\t= 3hrs

Substitute the values into the formula and divide.

s=\frac{120km}{3hrs}\\

s= 40 km/hr

<u>Train B</u>

Train B travelled a distance of 180 kilometers in 4 hours.

s=\frac{d}{t}\\d=180 km\\t= 4hrs

Substitute the values into the formula and divide.

s=\frac{180km}{4 hrs}\\

s= 45 km/hr

45 kilometers per hour is greater than 40 kilometers per hour, so Train B travelled faster.

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Which term is defined as the change in the direction of light when it goes from one medium into a different medium?
Vaselesa [24]
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8 0
3 years ago
A wire of length 5mm and Diameter 2m extends by 0.25 when a force of 50N was use. calculate the
bazaltina [42]

Answer and Explanation:

Data provided in the question

Force = 50N

Length = 5mm

diameter = 2.0m = 2\times 10^{-3}

Extended by = 0.25mm = 0.25\times 10^{-3}

Based on the above information, the calculation is as follows

a. The Stress of the wire is

= \frac{force\ applied}{area\ of \ circle}

here area of circle = perpendicular to the are i.e cross-sectional  i.e

= \frac{\pi d^{2}}{4}

= \frac{\pi(2\times 10^{-3})^2}{4}

Now place these above values to the above formula

= \frac{4\times 50}{\pi\times 4 \times 10^{-6}} \\\\ = \frac{50}{\pi}

= 15.92 MPa

As 1Pa = 1 by N m^2

So,

MPa = 10^6 N m^2

b. Now the strain of the wire is

= \frac{Change\ in\ length}{initial\ length} \\\\ = \frac{0.25\times 10^{-3}}{5}

= 5 \times 10^{-5}

3 0
3 years ago
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