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kupik [55]
3 years ago
15

The train 'A' travelled a distance is f 120 km in 3 hours , Whereas another train 'B' travelled a distance of 180 km in 4 hours

. Which train tracelled faster
Physics
2 answers:
Radda [10]3 years ago
6 0

Answer:

B train!

Explanation:

A train travelled at 40 km/hr. (120/3)

B train traveled at 45 km/hr (180/4)

Mama L [17]3 years ago
5 0

Answer:

Train B

Explanation:

Let's find each train's speed using the following formula.

s=\frac{d}{t}

where d is distance and t is time.

<u>Train A</u>

Train A travelled a distance of 120 kilometers in 3 hours.

s=\frac{d}{t}\\d=120 km\\t= 3hrs

Substitute the values into the formula and divide.

s=\frac{120km}{3hrs}\\

s= 40 km/hr

<u>Train B</u>

Train B travelled a distance of 180 kilometers in 4 hours.

s=\frac{d}{t}\\d=180 km\\t= 4hrs

Substitute the values into the formula and divide.

s=\frac{180km}{4 hrs}\\

s= 45 km/hr

45 kilometers per hour is greater than 40 kilometers per hour, so Train B travelled faster.

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A straight section of silver wire has a cross sectional area A=2.0 mm2. A total of 9.4×1018 electrons pass through the wire in 3
Sergio [31]

Answer:

8.08 x 10^-5 m

Explanation:

A = 2 mm^2 = 2 x 10^-6 m^2

Total number of electrons, N = 9.4 x 10^18

time, t = 3 s

n = 5.8 x 10^28 electrons/ m^3

Current, i = Q / t = N x e / t = (9.4 x 10^18 x 1.6 x 10^-19) / 3 = 0.5 A

Let vd be the drift velocity.

i = n e A vd

0.5 = 5.8 x 10^28 x 1.6 x 10^-19 x 2 x 10^-6 x vd

vd = 2.7 x 10^-5 m/s

Distance traveled by the electrons = velocity x time

                                                          = vd x t = 2.7 x 10^-5 x 3 = 8.08 x 10^-5 m  

3 0
3 years ago
Why do yall not hate us country people?
sveticcg [70]

Answer:

Because we don't?

Explanation:

4 0
3 years ago
Consider a glider flying at 400 meters altitude, when suddenly all its static ports become blocked by volcanic ash. The pressure
Furkat [3]

Answer:

the airspeed indicated by the pitot-tube driven airspeed indicator is 91.23m/s

Explanation:

Pitot tube

U = \sqrt{\frac{(p_t - p_s)2}{d} }

U = velocity(m/s)

p_t= stagnation pressure (pa)

p_s= static pressure (pa)

d = fluid density(kg/m³)

p_t = p_a_t_m + \frac{1}{2} dv^2

v = true velocity

= 101325 + 1/2(1.225)(25)²

p_t = 101,707.8125pa

p_s = 96,610pa

d = 1.225kg/m³

U = \sqrt{\frac{2(101,707.8125 - 96,610)}{1.225} } \\\\U = 91.23m/s

the airspeed indicated by the pitot-tube driven airspeed indicator is 91.23m/s

5 0
3 years ago
Water is stored in 5 places on earth.Name each place an dnote the phrase that water is in liquid solid,gas
podryga [215]
Atmosphere - gas
sea and oceans - liquid and solid
land -liquid and solid
living things and plants - liquid


6 0
3 years ago
A single-slit diffraction pattern is formed on a distant screen. Assuming the angles involved are small, by what factor will the
Novay_Z [31]

Answer:

It will be cut in half

Explanation:

The diffraction of a slit is given by the formula

a sin θ = m where

a = width of the slit,

λ = wavelength and

m = integer that determines the order of diffraction.

Next we divide both sides by a, we have

sin θ = m λ / a

Also, recall that

a’ = 2 a

Then we substitute in the previous equation

2asin θ' = m λ, if divide by 2a, we have

sin θ' = (m λ / 2a).

Now again, from the first equation, we said that sin θ = m λ / a, so we substitute

sin θ ’= sin θ / 2

Then we use trigonometry to find the width, we say

tan θ = y / L

Since the angle is small, we then have

tan θ = sin θ / cos θ

tan θ = sin θ, this then means that

sin θ = y / L

we will then substitute

y’ / L = y/L 1/2

y' = y / 2

this means that when the slit width is doubled the pattern width will then be halved

4 0
3 years ago
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