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3 years ago

Cinco litros de agua se divide en cuatro partes iguales, me tomo 2 partes ¿Cuánto me queda?

Mathematics

1 answer:

Alborosie3 years ago

8 0

Answer:

2 $\frac{1}{2}$

Step-by-step explanation:

5 ÷ 4 = 1 $\frac{1}{4}$

1 $\frac{1}{4}$ × 2 = 2 $\frac{2}{4}$ = 2 $\frac{1}{2}$

5 - 2 $\frac{1}{2}$ = 2 $\frac{1}{2}$

respuesta: 2 $\frac{1}{2}$

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Hezekiel runs 1000 m at a rateof 3 minutes per km. how long does he take to run 500 m

lana66690 [7]

Step-by-step explanation:

1 km = 1000 m

(hence the term "kilo" which means 1000).

so. he runs 1000 m at the rate of 3 minutes per km, that means 3 minutes per 1000 m.

now, we can see the solution already with our eyes.

but let's do it formally :

the rate or ratio between time and distance must be the same for the same speed.

so,

3 min / 1000 m = x min / 500 m

500 m × 3 min / 1000 m = x min

1/2 × 3 min = x min

3/2 = 1.5 min = x min

so, it takes him 1.5 minutes (90 seconds) to run 500 m.

3 0

2 years ago

Click the location of the point in the coordinate plane with the coordinates (–4, 3).

DerKrebs [107]

Answer:

I've put the red dot where location is.

Step-by-step explanation:

8 0

3 years ago

F(x)=x^2. what is g(x)?

Degger [83]

Answer:

Step-by-step explanation:

g(x) = 4x²

g(x) is steeper than f(x) and the ordered pair (1, 4) fits in option C:

g(1) = 4(1)² = 4

7 0

3 years ago

If the ratio of the length of segment AC to the length of segment CB is 3:1, what is the y-coordinate of point C?

Yuki888 [10]

Answer:

The coordinates of point C are (8,8.5)

Step-by-step explanation:

The picture of the question in the attached figure

Let

$(C_x,C_y)$ ----> coordinates of point C

we have that

The horizontal distance AB is equal to

$AB_x=10-2=8\ units$

The vertical distance AB is equal to

$AB_y=10-4=6\ units$

Find the horizontal coordinate of point C

we know that

$\frac{AC}{CB}=\frac{3}{1}$

$\frac{AC_x}{CB_x}=\frac{3}{1}$

$AC_x=3CB_x$ ----> equation A

$AC_x+CB_x=8$ ----> equation B

substitute equation A in equation B

$3CB_x+CB_x=8$

$4CB_x=8\\CB_x=2$

$AC_x=3(2)=6$

The x-coordinate of point C is equal to the x-coordinate of point A plus the horizontal distance between the point A and point C

$C_x=A_x+AC_x=2+6=8$

Find the vertical coordinate of point C

we know that

$\frac{AC}{CB}=\frac{3}{1}$

$\frac{AC_y}{CB_y}=\frac{3}{1}$

$AC_y=3CB_y$ ----> equation A

$AC_y+CB_y=6$ ----> equation B

substitute equation A in equation B

$3CB_y+CB_y=6$

$4CB_y=6\\CB_y=1.5$

$AC_y=3(1.5)=4.5$

The y-coordinate of point C is equal to the y-coordinate of point A plus the vertical distance between the point A and point C

$C_y=A_y+AC_y=4+4.5=8.5$

therefore

The coordinates of point C are (8,8.5)

5 0

3 years ago

Help would be much appreciated :)

makkiz [27]

Answer:

x = - 9

Step-by-step explanation:

<u>In order to find the vertical asymptotes make the denominator equal to zero and solve:</u>

2x + 18 = 0
2x = - 18
x = - 9

There is one vertical asymptote since the denominator is linear expression

6 0

2 years ago