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ioda
3 years ago
11

Farmer Brown is prepping his circular garden for the new spring/summer season of vegetables. The garden has to be larger than 25

square feet. If the diameter of the garden is 10 cm, what is the area? Does the farmer have enough space to plant his vegetables? Explain.
Mathematics
1 answer:
d1i1m1o1n [39]3 years ago
7 0

Answer:

The area is 78.5, the farmer does have enough space to plant his vegetables

Step-by-step explanation:

To find the area, you need to use the formula, A=πr², (make sure the diameter is turned into the radius by dividing by 2, in this case, it's 5 as the radius)

Plug in your numbers, A= 3.14(5)²

                                    A= 3.14(25)

The area is 78.5

So the farmer does have enough space to plant his vegetables since 78.5 is greater than 25

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The equation for the circle is (x-2)^2 + (y-1)^2 = 4<br><br> True<br> or<br> False???
jasenka [17]
True because the center is (2,1) and radius is 2
8 0
3 years ago
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A positive real number is 4 less than another. If the sum of the squares of the two numbers is 72, then find the numbers.
Illusion [34]

Answer:

Our two numbers are:

2+4\sqrt{2} \text{ and } 4\sqrt{2}-2

Or, approximately 7.66 and 3.66.

Step-by-step explanation:

Let the two numbers be <em>a </em>and <em>b</em>.

One positive real number is four less than another. So, we can write that:

b=a-4

The sum of the squares of the two numbers is 72. Therefore:

a^2+b^2=72

Substitute:

a^2+(a-4)^2=72

Solve for <em>a. </em>Expand:

a^2+(a^2-8a+16)=72

Simplify:

2a^2-8a+16=72

Divide both sides by two:

a^2-4a+8=36

Subtract 36 from both sides:

a^2-4a-28=0

The equation isn't factorable. So, we can use the quadratic formula:

\displaystyle x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}

In this case, <em>a</em> = 1, <em>b</em> = -4, and <em>c</em> = -28. Substitute:

\displaystyle x=\frac{-(-4)\pm\sqrt{(-4)^2-4(1)(-28)}}{2(1)}

Evaluate:

\displaystyle x=\frac{4\pm\sqrt{128}}{2}=\frac{4\pm8\sqrt{2}}{2}=2\pm4\sqrt{2}

So, our two solutions are:

\displaystyle x_1=2+4\sqrt{2}\approx 7.66\text{ or } x_2=2-4\sqrt{2}\approx-3.66

Since the two numbers are positive, we can ignore the second solution.

So, our first number is:

a=2+4\sqrt{2}

And since the second number is four less, our second number is:

b=(2+4\sqrt{2})-4=4\sqrt{2}-2\approx 3.66

6 0
3 years ago
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kotegsom [21]
From the given equation 
X+Y=20-->i
X-Y=14--->ii
add eq i and eq ii
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x=17
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4 years ago
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Determine whether the lines l1 and l2 are parallel, skew, or intersecting. If they intersect, find the point of intersection.
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Answer:

Step-by-step explanation:

Given are two lines equation in parametric form as

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Let us solve first two equatins for u and t and check whether 3rd equation is satisfied by this.

2*(i) -ii gives u = -3

t =0.5

Substitute in III equation

8(0.5)-2(-3) = 10 so  satisifed

These two are not skew lines

The point of intersection is got by substituting either t or u

Point of intersection (2, 9, 1)

4 0
4 years ago
The equation of a circle is given below. (x-0.5)^{2}+(y-3.5)^{2} = 16(x−0.5) 2 +(y−3.5) 2 =16left parenthesis, x, minus, 0, poin
Mashutka [201]

Answer:

<h2>The radius is 4 units long.</h2>

Step-by-step explanation:

The given equation is

(x-0.5)^{2} +(y-3.5)^{2} =16

This equation belongs to a circle, which center is at (0.5, 3.5) and its radius is 4.

You can deduct its elements, becase this equation of the circle is explicit, which means the constant term represents the square power of the radius. Solving that, we have

r^{2} = 16\\r=\sqrt{16}\\ r=4

Therefore, the radius is 4 units long.

3 0
3 years ago
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