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olasank [31]
3 years ago
11

Amalia is scuba diving at a position 24.25 feet below sea level. She descends 0.5 foot each minute for 25 minutes. What is Amali

a’s position compared to sea level after 25 minutes?
Mathematics
1 answer:
Inga [223]3 years ago
5 0

Answer:

36.75 feet below sea level

Step-by-step explanation:

Feet she descended in 25min

=0.5×25

=12.25

Therefore, the total feet she dived to

=12.25+24.25

=36.75

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Type the correct answer in the box.
Anna007 [38]

Answer:

y=-3x^2+11x-6

Step-by-step explanation:

Recall that one needs just three points on the plane to determine the form of the quadratic function that goes through them, because a quadratic function is defined by three parameters. We therefore can pick just  three simple ones that facilitate our calculations.

Realize that we need to find the parameters a,\,b, and c that gives as a function of the form: y=ax^2+bx+c that satisfies the values given in the table.

The simplest point to start with is the point (0,-6) which means that when x is 0 (zero), the value of y must be "-6". Placing such values in the general form, renders what the value of the parameter "c" should be:

y=ax^2+bx+c\\-6=a(0)^2+b(0)+c\\c=-6

So parameter c must be "-6".

Now let's use other simple values of "x" that facilitate our calculations, and include the value we just found, to reduce the number of unknowns:

point (1, 2):

y=ax^2+bx-6\\2=a(1)^2+b(1)-6\\8=a+b

Point (-1, -20):

y=ax^2+bx-6\\-20=a(-1)^2+b(-1)-6\\-14=a-b

Now, we can add these two equations term by term as they are, in order to get rid of the unknown "b":

a+b=8\\a-b=-14\\------\\2a+0=-6\\2a=-6\\a=\frac{-6}{2} \\a=-3

So we just found the value for parameter "a" = -3

Now we can use it as well as c = -6 in one of the equations we reduced above, in order to find the parameter (b) that we are missing:

a+b=8\\-3+b=8\\b=8+3\\b=11

So now we have the three parameters we need to define the quadratic function: y=-3x^2+11x-6

You can also check that the other points given in the table (2, 4) a,d (3, 0) are indeed points that belong to this quadratic function.

4 0
4 years ago
Mischa wrote the quadratic equation 0 = –x2 + 4x – 7 in standard form. What is the value of c in her equation
Zolol [24]

Mischa wrote the quadratic equation 0 = –x2 + 4x – 7 in standard form

The standard form of quadratic equation is

y= ax^2 + bx + c

When y=0 then the standard equation becomes

0= ax^2 + bx + c

Now we compare the given equation 0 = -x^2 + 4x - 7  with 0= ax^2 + bx + c and find the value of a, b,c

-x^2 can be written as -1x^2

0= ax^2 + bx + c

0 = -1x^2 + 4x - 7

a= -1 , b=4  and c=-7

The value of c is -7

4 0
4 years ago
Read 2 more answers
Help please will mark brainliest don’t answer unless your sure please
Lilit [14]
Are there other answers or just those 2
4 0
3 years ago
HELP PLZ WILL MARK YOU BRAINLIEST
pentagon [3]

Answer: 12

Step-by-step explanation:

If you look at K to M its the same length as M to J which would be 12

Hope this helped

4 0
3 years ago
Mason opens a savings account by making a $165.85 deposit. Every week, he deposits another $20.50 in the account.
Maslowich
C! Hope this helps :D
4 0
3 years ago
Read 2 more answers
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