Answer:
His average speed on the second day is 35 miles per hour.
Step-by-step explanation:
Consider the provided information.
On first day, he drove 2 hours longer than he drove on second day.
Let x = Number of hours he drove on second day.
Then x + 2 = Number of hours he drove on first day.
It is given that he drove a total of 18 hours.
Therefore,
![x + (x + 2) = 18](https://tex.z-dn.net/?f=x%20%2B%20%28x%20%2B%202%29%20%3D%2018)
![2x + 2= 18](https://tex.z-dn.net/?f=2x%20%2B%202%3D%2018)
![x=8](https://tex.z-dn.net/?f=x%3D8)
He drove 8 hours on second day.
x + 2 = 8+2=10
He drove 10 hours on first day.
Let y = speed driven on second day.
y + 5 = speed driven on first day.
As we know: Distance = speed × time
On first day he covers a distance of:
Distance = 10(y+5)
On second day he covers a distance of:
Distance = 8(y)
Total distance = Day 1 distance + Day 2 distance
![10(y+5) + 8(y) = 680\\10y+50+8y=680\\18y=630\\y=35](https://tex.z-dn.net/?f=10%28y%2B5%29%20%2B%208%28y%29%20%3D%20680%5C%5C10y%2B50%2B8y%3D680%5C%5C18y%3D630%5C%5Cy%3D35)
Hence, his average speed on the second day is 35 miles per hour.