d) neither parallel or perpendicular
6:20=9:30=3:10=18:60=16:160/3=12:40
Step-by-step explanation:
The question requires you to find value of x in the ratios given;
Start with the first pair
6:20 = 9:x
6/20 =9/x
6x=20*9
6x=180
x=180/6=30 ⇒⇒ 6:20 = 9:30
The second pair after replacing the value of x=30 will be
9:30 = x:10
9/30=x/10
90=30x
90/30 =x
3=x⇒⇒ 9:30 = 3:10
The third pair after replacing value of x=3 will be
3:10 =x:60
3/10 =x/60
180=10x
180/10 =x
18=x ⇒⇒ 3:10 = 18:60
The fourth pair after replacing value of x=18 will be;
18:60 = 16:x
18/60 = 16/x
18x=16*60
x= (16*60)/18 =160/3
x= 160/3 ⇒⇒⇒ 18:60 = 16: 160/3
The firth pair after replacing value of x=160/3 will be;
16: 160/3 =12:x
16x= 160/3 *12
16x = 160 * 4
x= (160 *4 )/16
x=40
⇒⇒ 16: 160/3 = 12: 40
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Ratios and proportions :brainly.com/question/9512748
Keywords : ratio, value of x, proportion
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Answer:
There is no solution to this answer.
Step-by-step explanation:
Leah's rate is 10x
Jason's rate is 20x
If you solve for 20x=10x, you get no solution. They are parallel lines.
Answer:
In words the answer is between t=0 and t=2.
In interval notation the answer is (0,2)
In inequality notation the answer is 0<t<2
Big note: You should make sure the function I use what you meant.
Step-by-step explanation:
I hope the function is h(t)=-16t^2+32t because that is how I'm going to interpret it.
So if we can find when the ball is on the ground or has hit the ground (this is when h=0) then we can find when it is in the air which is between those 2 numbers.
0=-16t^2+32t
0=-16t(t-2)
So at t=0 and t=2
So the ball is in the air between t=0 and t=2
Interval notation (0,2)
Inequality notation 0<t<2
