The question is incomplete, here is the complete question:
The half-life of a certain radioactive substance is 46 days. There are 12.6 g present initially.
When will there be less than 1 g remaining?
<u>Answer:</u> The time required for a radioactive substance to remain less than 1 gram is 168.27 days.
<u>Step-by-step explanation:</u>
All radioactive decay processes follow first order reaction.
To calculate the rate constant by given half life of the reaction, we use the equation:
where,
= half life period of the reaction = 46 days
k = rate constant = ?
Putting values in above equation, we get:
The formula used to calculate the time period for a first order reaction follows:
where,
k = rate constant =
t = time period = ? days
a = initial concentration of the reactant = 12.6 g
a - x = concentration of reactant left after time 't' = 1 g
Putting values in above equation, we get:
Hence, the time required for a radioactive substance to remain less than 1 gram is 168.27 days.
9514 1404 393
Answer:
y = -6x +9
y = 9·(1/3)^x
Step-by-step explanation:
In each case, the y-intercept is 9.
Linear
The slope is rise/run = (3-9)/(1-0) = -6, so the equation is ...
y = mx + b . . . . . . . slope m, intercept b
y = -6x +9
Exponential
The ratio of value at x=1 to that at x=0 is 3/9 = 1/3. That is the "growth factor," so the equation is ...
y = 9·(1/3)^x
D) 35
Use the slope formula
(y2-y1)
______
(x2-x1)
(70-35)
______= 35/1
(1 - 0)
Answer:
i cant see it take another picture plz
Step-by-step explanation: