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mariarad [96]
3 years ago
10

Your yard is in a shape of a trapezoid

Mathematics
1 answer:
g100num [7]3 years ago
4 0

Answer: You would tell him 1,425ft².

Step-by-step explanation:

f

First, you need to know the equation for finding the area of a trapezoid, which is <em><u>½</u></em><em><u>h</u></em><em><u>(</u></em><em><u>b1</u></em><em><u>+</u></em><em><u>b2</u></em><em><u>)</u></em> .

When you plug in all the number you have into the equation, you have a new equation essentially that says, <em><u>½×30(65+50)</u></em> .

When you start solving the equation, you need to do parentheses first, so <em><u>65+30</u></em>, which would get you 95. This would then turn the equation into <em><u>½×30(95)</u></em> .

Next, you have to do <em><u>30×95</u></em>, which would come out to be 2850. When you do this, your equation would now be <em><u>½</u></em><em><u>×</u></em><em><u>2</u></em><em><u>8</u></em><em><u>5</u></em><em><u>0</u></em> , or essentially <em><u>2850</u></em><em><u>÷</u></em><em><u>2</u></em> .

When you do the last and final step of the problem, which is <em><u>½×2850</u></em>, you would get 1425. But since it's area, your answer would <em><u>1425ft²</u></em>.

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{\huge{\fcolorbox{yellow}{red}{\orange{\boxed{\boxed{\boxed{\boxed{\underbrace{\overbrace{\mathfrak{\pink{\fcolorbox{green}{blue}{Answer}}}}}}}}}}}}}

(i)

\sf{a_n = 20 \times  {( \frac{2}{3} )}^{n - 1} }

(ii)

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Step-by-step explanation:

\underline\red{\textsf{Given :-}}

height of ball (a) = 10m

fraction of height decreases by each bounce (r) = 2/3

\underline\pink{\textsf{Solution :-}}

<u>(</u><u>i</u><u>)</u><u> </u><u>We</u><u> </u><u>will</u><u> </u><u>use</u><u> </u><u>here</u><u> </u><u>geometric</u><u> </u><u>progression</u><u> </u><u>formula</u><u> </u><u>to</u><u> </u><u>find</u><u> </u><u>height</u><u> </u><u>an</u><u> </u><u>times</u>

{\blue{\sf{a_n = a {r}^{n - 1} }}} \\ \sf{a_n = 20 \times  { \frac{2}{3} }^{n - 1} }

(ii) <u>here</u><u> </u><u>we</u><u> </u><u>will</u><u> </u><u>use</u><u> </u><u>the</u><u> </u><u>sum</u><u> </u><u>formula</u><u> </u><u>of</u><u> </u><u>geometric</u><u> </u><u>progression</u><u> </u><u>for</u><u> </u><u>finding</u><u> </u><u>the</u><u> </u><u>total</u><u> </u><u>nth</u><u> </u><u>impact</u>

<u>\orange {\sf{S_n = a \times  \frac{(1 -  {r}^{n} )}{1 - r} }} \\  \sf S_n = 20 \times  \frac{1 -  ( { \frac{2}{3} })^{n}  }{1 -  \frac{2}{3} }  \\   \sf S_n = 20 \times  \frac{1 -  {( \frac{2}{3}) }^{n} }{ \frac{1}{3} }  \\  \sf S_n = 3 \times 20 \times  \{1 - ( { \frac{2}{3}) }^{n}  \} \\   \purple{\sf S_n = 60 \{1 -  { \frac{2}{3} }^{n}  \}}</u>

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