Question

Please can someone help????

Answer 1

Proof:

Consider $\triangle WXZ, \triangle YZX:$

$\overline W\overline X = \overline Y\overline Z$ (given)

$\angle WXZ = \angle YZX$ (alternate angles are equal, $\overline W\overline X\parallel \overline Y\overline Z$)

$\overline Z \overline X$ is a common side

∴ $\triangle WXZ \cong \triangle YZX$ (SAS)

Hope this helps :)