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tiny-mole [99]
3 years ago
10

Determine whether 2/3 and 16/24 are equivalent ratios. choose yes or no

Mathematics
1 answer:
Phoenix [80]3 years ago
6 0

Answer:

Yes, they are equivalent

Step-by-step explanation:

Divide the second numerator by the first numerator

Divide the second denominator by the first denominator

Compare the quotients and if they are the same then the fractions are equivalent

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Given: Quadrilaterals ABCD ~ EFGH , with measure of angle A = 47 degrees, measure of angle B = 39 degrees, and measure of angle
kaheart [24]

Answer:

The answer is below

Step-by-step explanation:

Two polygons are said to be congruent if they have the same size and shape that is their corresponding angles and sides are equal.

Hence since Quadrilaterals ABCD is congruent to EFGH, then their corresponding angles and sides are equal.

In quadrilateral ABCD:

∠A + ∠B + ∠C + ∠D = 360° (sum of angles in a quadrilateral)

Substituting:

47 + 39 + 112 + ∠D = 360

∠D + 198 = 360

∠D = 360 - 198

∠D = 162°

The image of Quadrilaterals ABCD and EFGH is not given but let us assume that they have the same orientation, hence:

∠A = ∠E = 47°

∠B = ∠F = 39°

∠C = ∠G = 112°

∠D = ∠H = 162°

3 0
2 years ago
I need help!!! As fast as possible!!!!
ale4655 [162]

Answer:

x = 44º

Step-by-step explanation:

∡P  = 360 - 112*2 = 136º

∡A = x = 180 - 136º = 44º

6 0
3 years ago
Read 2 more answers
Solve for m: (y_1 - y_2) = m(x_1 - x_2)
Mashutka [201]
y_1-y_2=m(x_1-x_2)\\
m=\dfrac{y_1-y_2}{x_1-x_2}
5 0
3 years ago
Blanca runs 8 laps around the track each day to train for an endurance race. She times each lap to practice her pacing for the r
Artist 52 [7]

Answer:

A graph shows lap time (seconds) labeled 82 to 98 on the horizontal axis and the number of laps on the vertical axis. 1 lap was 82 to 84 seconds.  4 laps were 84 to 86 seconds. 2 laps were 86 to 88 seconds. 4 laps were 88 to 90 seconds. 6 laps were 90 to 92 seconds. 5 laps were 92 to 94 seconds. 2 laps were 94 to 96 seconds. 0 laps were 96 to 98 seconds

Step-by-step explanation:

The given table is presented as follows;

\begin{array}{ccc}Day \ 1 \ lap \ times \ (seconds)&Day \ 2 \ lap \ times \ (seconds)&Day \ 3 \ lap \ times \ (seconds)\\83&87&85\\92&90&86\\91&92&91\\89&91&93\\94&92&91\\93&95&89\\88&90&88\\84&85&84\end{array}The number of laps in the range 82 to 84 seconds = 1

The number of laps in the range 84 to 86 seconds = 4

The number of laps in the range 86 to 88 seconds = 2

The number of laps in the range 88 to 90 seconds = 4

The number of laps in the range 90 to 92 seconds = 6

The number of laps in the range 92 to 94 seconds = 5

The number of laps in the range 94 to 96 seconds = 2

The number of laps in the range 96 to 98 seconds = 0

Therefore, the histogram that represents Blanca's lap times for the three days of practice is described as follows;

A graph shows lap time (seconds) labeled 82 to 98 on the horizontal axis and the number of laps on the vertical axis. 1 lap was 82 to 84 seconds.  4 laps were 84 to 86 seconds. 2 laps were 86 to 88 seconds. 4 laps were 88 to 90 seconds. 6 laps were 90 to 92 seconds. 5 laps were 92 to 94 seconds. 2 laps were 94 to 96 seconds. 0 laps were 96 to 98 seconds

5 0
3 years ago
1
olga nikolaevna [1]

Answer:

Fraction of the original board left = \frac{2}{15}

Step-by-step explanation:

Let the length of the board is = l feet

Marty saws off \frac{1}{5} of a wooden board.

Length of the board left = l - (\frac{1}{5})l

                                        = (\frac{4}{5})l feet

He saws off \frac{3}{4}th of the remaining board,

Board left = (\frac{4}{5})l-[(\frac{4}{5})l\times (\frac{3}{4})]

                = \frac{4}{5}l-\frac{3}{5}l

                = \frac{1}{5}l feet

He finally saws off \frac{1}{3}rd of the remaining board.

Board left = \frac{1}{5}l-[\frac{1}{5}\times \frac{1}{3}]l

                = (\frac{1}{5}-\frac{1}{15})l

                = \frac{2}{15}l feet

Fraction of the original board left = \frac{\frac{2}{15}l}{l}

                                                       = \frac{2}{15}

6 0
3 years ago
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