Answer:
The answer is below
Step-by-step explanation:
Two polygons are said to be congruent if they have the same size and shape that is their corresponding angles and sides are equal.
Hence since Quadrilaterals ABCD is congruent to EFGH, then their corresponding angles and sides are equal.
In quadrilateral ABCD:
∠A + ∠B + ∠C + ∠D = 360° (sum of angles in a quadrilateral)
Substituting:
47 + 39 + 112 + ∠D = 360
∠D + 198 = 360
∠D = 360 - 198
∠D = 162°
The image of Quadrilaterals ABCD and EFGH is not given but let us assume that they have the same orientation, hence:
∠A = ∠E = 47°
∠B = ∠F = 39°
∠C = ∠G = 112°
∠D = ∠H = 162°
Answer:
x = 44º
Step-by-step explanation:
∡P = 360 - 112*2 = 136º
∡A = x = 180 - 136º = 44º
Answer:
A graph shows lap time (seconds) labeled 82 to 98 on the horizontal axis and the number of laps on the vertical axis. 1 lap was 82 to 84 seconds. 4 laps were 84 to 86 seconds. 2 laps were 86 to 88 seconds. 4 laps were 88 to 90 seconds. 6 laps were 90 to 92 seconds. 5 laps were 92 to 94 seconds. 2 laps were 94 to 96 seconds. 0 laps were 96 to 98 seconds
Step-by-step explanation:
The given table is presented as follows;
The number of laps in the range 82 to 84 seconds = 1
The number of laps in the range 84 to 86 seconds = 4
The number of laps in the range 86 to 88 seconds = 2
The number of laps in the range 88 to 90 seconds = 4
The number of laps in the range 90 to 92 seconds = 6
The number of laps in the range 92 to 94 seconds = 5
The number of laps in the range 94 to 96 seconds = 2
The number of laps in the range 96 to 98 seconds = 0
Therefore, the histogram that represents Blanca's lap times for the three days of practice is described as follows;
A graph shows lap time (seconds) labeled 82 to 98 on the horizontal axis and the number of laps on the vertical axis. 1 lap was 82 to 84 seconds. 4 laps were 84 to 86 seconds. 2 laps were 86 to 88 seconds. 4 laps were 88 to 90 seconds. 6 laps were 90 to 92 seconds. 5 laps were 92 to 94 seconds. 2 laps were 94 to 96 seconds. 0 laps were 96 to 98 seconds
Answer:
Fraction of the original board left = 
Step-by-step explanation:
Let the length of the board is = l feet
Marty saws off
of a wooden board.
Length of the board left = l - 
=
feet
He saws off
of the remaining board,
Board left = ![(\frac{4}{5})l-[(\frac{4}{5})l\times (\frac{3}{4})]](https://tex.z-dn.net/?f=%28%5Cfrac%7B4%7D%7B5%7D%29l-%5B%28%5Cfrac%7B4%7D%7B5%7D%29l%5Ctimes%20%28%5Cfrac%7B3%7D%7B4%7D%29%5D)
= 
=
feet
He finally saws off
rd of the remaining board.
Board left = ![\frac{1}{5}l-[\frac{1}{5}\times \frac{1}{3}]l](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B5%7Dl-%5B%5Cfrac%7B1%7D%7B5%7D%5Ctimes%20%5Cfrac%7B1%7D%7B3%7D%5Dl)
= 
=
feet
Fraction of the original board left = 
= 