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3 years ago

Help ME PLSSS 13 points

Mathematics

2 answers:

Greeley [361]3 years ago

8 0

Answer:

Step-by-step explanation:

Ber [7]3 years ago

8 0

Answer:

Answer is 6 pay attention to class kid

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Mrs.Alvarez bought a new car her monthly payments are $525.If she will pay a total of $25,200 in payments,write and solve a mult

yaroslaw [1]

525 * N = 25200

you can solve it i expect.

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3 years ago

What is the value of this expression?

solmaris [256]

$\frac{11}{12}-\frac{1}{3} +\frac{2}{6} = \frac{11}{12}-\frac{1}{3} +\frac{1}{3} =\frac{11}{12}$

Answer: 11/12

Ok done. Thank to me :>

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2 years ago

Simplify 2y+4x=16x +6y

AleksAgata [21]

The Answer would be y=-3x

8 0

3 years ago

Nuts.com sells raw almonds for $10 per pound and roasted pistachios for $12 per pound. Christopher spends $70, before taxes and

sp2606 [1]

Christopher purchased 2.8 pounds of almonds and 3.5 pounds to roasted pistachios.

Step-by-step explanation:

Cost of almonds per pound = $10

Cost of roasted pistachios = $12

Total amount spent = $70

Weight of nuts = 6.3

Let,

Weight of almonds = x

Weight of roasted pistachios = y

According to given statement;

x+y=6.3 Eqn 1

10x+12y=70 Eqn 2

Multiplying Eqn 1 by 10

$10(x+y=6.3)\\10+10y=63\ \ \ Eqn\ 3$

Subtracting Eqn 3 from Eqn 2;

$(10x+12y)-(10x+10y)=70-63\\10x+12y-10x-10y=7\\2y=7$

Dividing both sides by 2

$\frac{2y}{2}=\frac{7}{2}\\y=3.5$

Putting y=3.5 in Eqn 1

$x+3.5=6.3\\x=6.3-3.5\\x=2.8$

Christopher purchased 2.8 pounds of almonds and 3.5 pounds to roasted pistachios.

Keywords: linear equations, elimination method

Learn more about elimination method at:

#LearnwithBrainly

8 0

3 years ago

Suppose that 15% of the fields in a given agricultural area are infested with the sweet potato whitefly. One hundred fields in t

hram777 [196]

Answer:

a. $\mu=15$

b. $\mu=7.8586 \ and \ \mu=22.1414$

c. Choice A- Based on limits above, it is unlikely that we would see x = 45, so it might be possible that the trials are not independent.

Step-by-step explanation:

a.Binomial distribution is defined by the expression

$P(X=k)=C_k^n.p^k.(1-p)^{n-k}$

Let n be the number of trials, $n=100$

and p be the probability of success, $p=15\%$

The mean of a binomial distribution is the probability x sample size.

$\mu=np=100\times0.15=15$

b.Limits within which p is approximately 95%

sd of a binomial distribution is given as: $\sigma=\sqrt npq\\q=1-p$

Therefore, $\sigma=\sqrt(100\times0.015\times0.85)=3.5707$

Use the empirical rule to find the limits. From the rule, approximately 95% of the observations are within to standard deviations from mean.

$sd_1=>\mu-2\sigma=15-2\times3.3507=7.8586\\sd_2=>\mu-2\sigma=15+2\times3.3507=22.1414$

Hence, approximately 95% of the observations are within 7.8586 and 22.1414 (areas of infestation).

c. $x=45$ is not within the limits in b above (7.8586,22.1414). X=45 appears to be a large area of infestation. A.Based on limits above, it is unlikely that we would see x = 45, so it might be possible that the trials are not independent.

4 0

4 years ago