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2 years ago

Help find the missing segment???

Mathematics

2 answers:

SVEN [57.7K]2 years ago

6 0

(9/6) = (15/?)
9? = 90
? = 10

zimovet [89]2 years ago

3 0

Answer:

Step-by-step explanation:

The similarity of triangles says that the ratio between the corresponding sides is the same.

See that, if 9/6 = 1.5

15 / x = 1.5

We solve the equation

we multiply 15/x by x to remove the fraction

(15 / x) x = 1.5 * x

It result

15 = 1.5x

Now, we divide everything by 1.5 to leave the X alone

15 / 1.5 = (1.5x)/1.5

It result

15/1.5 = x

10 = x

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Vanyuwa [196]

la respuesta correcta es: 5,700

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2 years ago

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Please answer question now

nata0808 [166]

Answer:

469.42 ft²

Step-by-step explanation:

Law of sines;

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2 years ago

Sarah has two similar rectangular boxes. The dimensions of Box 1 are four times those of Box 2.

Elena-2011 [213]

Answer: 16

Step-by-step explanation:

an area is always calculated by multiplying 2 dimensions.

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therefore, when both dimensions of an area are enlarged 4 times, then the area is enlarged 4×4 = 16 times.

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just think

16×a + 16×b + 16×c ... = 16×(a+b+c+...)

4 0

2 years ago

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Which of the following functions f : {0, 1, 2, 3} ! {0, 1, . . . , 7} are one-to-one?

allsm [11]

Answer:

1. No.

$f(0)=0\\1^2=1; \text{then } f(1)=1\\2^2=4\equiv 4 \text{ mod 8}; \text{then } f(2)=4\\3^2=9\equiv 1 \text{mod 8 }; \text{then } f(3)=1$

Since f(1)=f(3) and $1\neq 3$ then f isn't one-to-one.

2. No

$f(0)=0\\1^3=1\equiv 1\text{ mod 8}; \text{then } f(1)=1\\2^3=8\equiv 0\text{ mod 8}; \text{then } f(2)=0\\3^3=27\equiv 3 \text{ mod 8}; \text{then } f(3)=3$

Since f(0)=f(2) and $0\neq 2$ then f isn't one-to-one.

3. No

$0^3-8=-8\equiv 0\text{ mod 8}; \text{then } f(0)=0\\1^3-8=-7\equiv 1\text{ mod 8}; \text{then } f(1)=1\\2^3-8=0\equiv 0 \text{ mod 8}; \text{then } f(2)=0\\3^3-8=27-8=19\equiv 3 \text{ mod 8}; \text{then } f(3)=3\\$

Since f(0)=f(2) and $0\neq 2$ then f isn't one-to-one.

4. Yes

$0^3+2*0=0; \text{then } f(0)=0\\1^3+2*1=3\equiv 3\text{ mod 8}; \text{then } f(1)=3\\2^3+2*2=8+4=12\equiv 4 \text{ mod 8}; \text{then } f(2)=4\\3^3+2*3=27+6=33\equiv 1\text{ mod 8}; \text{then } f(3)=1$

Since $f(0)\neq f(1)\neq f(2) \neq f(3)$ , then f is one-to-one

5. Since f(1)=f(3) and $1\neq 3$ then, f isn't one-to-one

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If you have one per box you got 20 broken in all.

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3 years ago