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wolverine [178]

2 years ago

10

Find the difference. 89 – 52.05

2 answers:

Elanso [62]2 years ago

7 0

Answer:

36.95

Step-by-step explanation:

89- 52.05

=36.95

hammer [34]2 years ago

7 0

Answer:

The answer is 36.95.

Step-by-step explanation:

When you subtract, you are taking away one amount from another amount. In this case, we are taking 52.05 away from 89.

#teamtrees #WAP (Water And Plant)

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Why is 8(s-3) considered a single term when (s-3) is the difference of two terms?

jok3333 [9.3K]

When you have 8(s-3) you are find a product of 8 times whatever s-3 is however s-3 you are find the difference between whatever s is and 3.

4 0

2 years ago

Which expression calculates the speed in meters per second of an object that travels a distance of 100 m every 20 s?

patriot [66]

Speed=distance/time so it would be 100/20

5 0

3 years ago

Read 2 more answers

Please help me!!!!!!!

Helen [10]

First we will find the value of x.

To find the value of x we can add angle Q and angle O and set them equal to 180 and solve for x.

We will be setting them equal to 180 since the opposite angles of an inscribed quadrilateral are supplementary.

angle Q + angle O = 180
6x - 5 + x + 17 = 180
7x +12 = 180
7x = 168
x = 24

Now we can use 24 for x and find the value of angle QRO

angle QRO = 2x + 19
angle QRO = 2(24) + 19
angle QRO = 48 + 19
angle QRO = 67

So the answer choice B is the right answer.

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6 0

3 years ago

What are the real zeros of x^3+4x^2-9x-36

Katyanochek1 [597]

Answer:

$x = -4\\x = -3\\x = 3$

Step-by-step explanation:

To find the real zeros you must match the function to zero and factor the expression.

We have a polynomial of degree 3.

We try to group the terms to perform the factorization

$x ^ 3 + 4x ^ 2-9x-36 = 0\\\\x ^ 2(x + 4) - 9(x + 4) = 0$

Now we take (x + 4) as a common factor

$(x + 4)(x ^ 2 -9) = 0$

If we have an expression of the form $(a ^ 2-b ^ 2)$ we know that this expression is equivalent to:

$(a ^ 2-b ^ 2) = (a + b)(a-b)$

In this case

$a = x\\b = 3$

So:

$(x ^ 2 -9) = (x + 3)(x-3)$

Finally:

$x ^ 3 + 4x ^ 2-9x-36 = (x + 4)(x + 3)(x-3) = 0$

The solutions are:

$x = -4\\x = -3\\x = 3$

6 0

3 years ago

Which equation is y = 9x2 + 9x – 1 rewritten in vertex form?

Anastasy [175]

Answer:

$y = 9(x +\frac{1}{2}) ^ 2 -\frac{13}{4}$

Step-by-step explanation:

An equation in the vertex form is written as

$y = a (x-h) + k$

Where the point (h, k) is the vertex of the equation.

For an equation in the form $ax ^ 2 + bx + c$ the x coordinate of the vertex is defined as

$x = -\frac{b}{2a}$

In this case we have the equation $y = 9x^2 + 9x - 1$ .

Where

$a = 9\\\\b = 9\\\\c = -1$

Then the x coordinate of the vertex is:

$x = -\frac{9}{2(9)}\\\\x = -\frac{9}{18}\\\\x = -\frac{1}{2}$

The y coordinate of the vertex is replacing the value of $x = -\frac{1}{2}$ in the function

$y = 9 (-0.5) ^ 2 + 9 (-0.5) -1\\\\y = -\frac{13}{4}$

Then the vertex is:

$(-\frac{1}{2}, -\frac{13}{4})$

Therefore The encuacion excrita in the form of vertice is:

$y = a(x +\frac{1}{2}) ^ 2 -\frac{13}{4}$

To find the coefficient a we substitute a point that belongs to the function $y = 9x^2 + 9x - 1$

The point (0, -1) belongs to the function. Thus.

$-1 = a(0 + \frac{1}{2}) ^ 2 -\frac{13}{4}$

$-1 = a(\frac{1}{4}) -\frac{13}{4}\\\\a = \frac{-1 +\frac{13}{4}}{\frac{1}{4}}\\\\a = 9$

<em>Then the written function in the form of vertice is</em>

$y = 9(x +\frac{1}{2}) ^ 2 -\frac{13}{4}$

7 0

3 years ago