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pantera1 [17]
2 years ago
9

Which is equal to 4 hectometers? 0.04 kilometers 0.4 kilometers 0.004 kilometers

Mathematics
2 answers:
san4es73 [151]2 years ago
5 0

Answer:

0.4 km

Step-by-step explanation:

saul85 [17]2 years ago
4 0

Answer:

0.04 kilometers

Step-by-step explanation:

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The universal set in this diagram is the set of integers from 1 to 15. place the integers in the correct place in the venn diagr
neonofarm [45]

Answer:


Step-by-step explanation:

Given :  universal set in this diagram is the set of integers from 1 to 15.

Solution :

The intersection of odd integer,multiples of 3 and Factors of 15 are 3,15

The intersection of odd integer and Factors of 15 are 1,5

The intersection of odd integer,multiples of 3 is 9

The remaining multiples of 3 are 6,12

The remaining odd integers are 7,11,13

Now the remaining integers are 2,4,8,10,14 and these integers must be placed in the boxes outside the circles Since they does not belong any intersection or odd integer or factor of 15 .

Refer the attached figure for the answer.

3 0
3 years ago
Read 2 more answers
Which are acute, obtuse, or right?
qaws [65]
5,7 and 8 are right angles, and 6 is an acute angle this is because of u look at 9 and 10 you can see a little box looking thing under the h and if u do that to all of them 5, 7 and 8 can fit the little box but 6 you can’t because it is an acute angle. Hope this helped!
8 0
3 years ago
When building a house, you have the choice of seven different floor plans, brick or stone exterior and carpet or hardwood floori
Yakvenalex [24]
11 im pretty sure....
4 0
3 years ago
Solve for x. <br><br> x<br> 4<br> = <br> 3<br> 8
geniusboy [140]

Answer:

x=6

Step-by-step explanation:

( 8 ) ⋅ ( 3 ) = ( x ) ⋅ ( 4 )

6 0
3 years ago
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Now there is a square city of unknown size with a gate at the center of each side. There is a tree 20 b from the north gate. Tha
Brums [2.3K]

Answer:

The length of each side of the city is 250b

Step-by-step explanation:

Given

a = 20 --- tree distance from north gate

b =14 --- movement from south gate

c = 1775 --- movement in west direction from (b)

See attachment for illustration

Required

Find x

To do this, we have:

\triangle ADE \sim \triangle ACB --- similar triangles

So, we have the following equivalent ratios

AE:DE = AB:CB

Where:

AE = 20\\ DE = x/2 \\ AB = 20 + x + 14 \\ CB = 1775

Substitute these in the above equation

20:x/2 = 20 + x + 14: 1775

20:x/2 = x + 34: 1775

Express as fraction

\frac{20}{x/2} = \frac{x + 34}{1775}

\frac{40}{x} = \frac{x + 34}{1775}

Cross multiply

x *(x + 34) = 1775 * 40

Open bracket

x^2 + 34x = 71000

Rewrite as:

x^2 + 34x - 71000 = 0

Expand

x^2 + 284x -250x - 71000 = 0

Factorize

x(x + 284) -250(x + 284)= 0

Factor out x + 284

(x - 250)(x + 284)= 0

Split

x - 250 = 0 \ or\ x + 284= 0

Solve for x

x = 250 \ or\ x =- 284

x can't be negative;

So:

x = 250

6 0
3 years ago
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