Question

Find the anti derivative of f(x)=fourth root(x^3)+cube root(x^2)

Answer 1

$\int {( \sqrt[4]{ x^{3} } + \sqrt[3]{ x^{2} }) } \, dx = \\ = \int {( x^{3/4}+ x^{2/3} )} \, dx = \\ \frac{ x^{7/4} }{7/4}+ \frac{ x^{5/3} }{5/3}+C = \\ \frac{4 \sqrt[4]{ x^{7} } }{7}+ \frac{3 \sqrt[3]{ x^{5} } }{5}+C$