The graph adequately represents the following case
"The number of employees at a store increased at a constant rate for 5 years. There was a decrease in the number of employees for 2 years. Then the number of employees increased at a greater constant rate for the next few years."
Step-by-step explanation:
To solve the above-mentioned problems we need to filter the results through analysing the options given-
We have to keep in mind that-
- For an increase in value/quantity- the graph would be on an upswing
- For decrease in value/quantity- The graph would be in declining mode
- For constant value- horizontal graph line parallel to the x-axis
Now going through the options-
option 1:-
David drove at a constant speed initially- throughout the graph no horizontal line is present, hence this condition does not represent the graph.
option 2:-
test scores increased and then decline- In this condition only two phases are mentioned, whereas in the graph three different phases are present. Hence this condition too does not represent the graph.
option 3:-
After the period of slow.- The graph starts with an upswing. hence this condition too does not represent the graph.
option 4:-
Employees increased and then declined and then again increased. All the above condition corroborates to the above-mentioned graph. hence this condition is represented in the graph
Quarterly payment (before Svc Chg): PV 35,125, N 40, R 1.86% computes to Annuity of 1,252.70
Total paid (1,252.70 x 40) 50,108 - 35,125 = 14,983 Interest paid + 5,180.70 Svc Chg = 20,163.70, of which Svc Chg was 25.69%
According to formula
P(1 - R/100)^ T
P =PRICE
R =RATE OF DEPRECIATION
T= TIME
answer is $47320
3/4 or 0.75 or just 75%. doesn't get much simpler
