Answer:
x = 8
Step-by-step explanation:
6x - 3 = 5x + 5
Move variable to the left hand side and change their sign.
Calculate like terms.
Move constant to the right hand side and change their sign.
<u>Check our answer :-</u>
6x -3 = 5x + 5
plug the 8 as x.
- 6 ( 8 ) - 3 = 5 ( 8 ) + 5
- 48 - 3 = 40 + 5
- 45 = 45
LHS = RHS
Answer:
369.7 mL of medication
Step-by-step explanation:
How many mL of medication are needed to last 10 days if the dose of medication is 2.5 tsp TID (three times a day)?
From the above question,
The dosage of the medication =
2.5 tsp 3 times a day
= 2.5 × 3 = 7.5 tsp per day.
Since
1 day = 7.5 tsp
10 days = x tsp
Cross Multiply
x = 10 × 7.5 tsp
x = 75 tsp of medication for 10 days.
Step 2
It is important to note that:
1 tsp = 4.929 mL
75 tsp = x mL
Cross Multiply
x = 75 × 4.929 mL
x = 369.669 mL of medication
Approximately = 369.7 mL of medication
He won about 25% because 6/12 would be 1/2 and 3 is 1/2 of 6 or a 1/4 so 25%
Answer: 2 meters.
Step-by-step explanation:
Let w = width of the cement path.
Dimensions of pool : Length = 15 meters , width = 9 meters
Area of pool = length x width = 15 x 9 = 135 square meters
Along width cement path, the length of region = 
width = 
Area of road with pool = 
Area of road = (Area of road with pool ) -(area of pool)
![\Rightarrow\ 112 =4w^2+48w+135- 135\\\\\Rightarrow\ 112= 4w^2+48w\\\\\Rightarrow\ 4 w^2+48w-112=0\\\\\Rightarrow\ w^2+12w-28=0\ \ \ [\text{Divide both sides by 4}]\\\\\Rightarrow\ w^2+14w-2w-28=0\\\\\Rightarrow\ w(w+14)-2(w+14)=0\\\\\Rightarrow\ (w+14)(w-2)=0\\\\\Rightarrow\ w=-14\ or \ w=2](https://tex.z-dn.net/?f=%5CRightarrow%5C%20112%20%3D4w%5E2%2B48w%2B135-%20135%5C%5C%5C%5C%5CRightarrow%5C%20112%3D%204w%5E2%2B48w%5C%5C%5C%5C%5CRightarrow%5C%204%20w%5E2%2B48w-112%3D0%5C%5C%5C%5C%5CRightarrow%5C%20w%5E2%2B12w-28%3D0%5C%20%5C%20%5C%20%5B%5Ctext%7BDivide%20both%20sides%20by%204%7D%5D%5C%5C%5C%5C%5CRightarrow%5C%20w%5E2%2B14w-2w-28%3D0%5C%5C%5C%5C%5CRightarrow%5C%20w%28w%2B14%29-2%28w%2B14%29%3D0%5C%5C%5C%5C%5CRightarrow%5C%20%28w%2B14%29%28w-2%29%3D0%5C%5C%5C%5C%5CRightarrow%5C%20%20w%3D-14%5C%20or%20%5C%20w%3D2)
width cannot be negative, so w=2 meters
Hence, the width of the road = 2 meters.
