She has to make 400 in order to raise $200 because if she was selling them for $1 she would need 200 so just double that since she's only selling them for $0.50
Answer:
30/552
Step-by-step explanation:
In order to solve this problem you need to multiply the probability of getting grape for the first gumball with the probability of getting grape for the second gumball. Since there are 6 grape gumballs and a total of 24 gumballs (6*4). Then the probability of getting grape for the firs one is

Now there are only 5 grape gumballs available and one less in the total supply, therefore the probability of getting grape in the second try is

Finally we multiply them together to find the probability of getting two grapes in a row.
= 
The system of the equation doesn't give the solution at (-3, -6).
<h2>Given to us</h2>
<h3>Equation 1,</h3>
-4x+y = 6
solve for y

<h3>Equation 2,</h3>
5x-y =21
substitute the value of y in equation 2,

Substitute the value of x in equation 2,

We can see that the solution of the two equations is at (27, 114). Also, it can be verified by plotting the line on the graph.
Hence, the system of the equation doesn't give the solution at (-3, -6).
Learn more about system of equations:
brainly.com/question/12895249
<span>Probability = 0.063
Fourth try = 0.0973
Let X be the number of failed attempts at passing the test before the student passes. This
is a negative binomial or geometric variable with x â {0, 1, 2, 3, . . .}, p = P(success) = 0.7
and the number of successes to to observe r = 1. Thus the pmf is nb(x; 1, p) = (1 â’ p)
xp.
The probability P that the student passes on the third try means that there were x = 2
failed attempts or P = nb(2, ; 1, .7) = (.3)2
(.7) = 0.063 . The probability that the student
passes before the third try is that there were two or fewer failed attmpts, so P = P(X ≤
2) = nb(0, ; 1, .7) + nb(1, ; 1, .7) + nb(2, ; 1, .7) = (.3)0
(.7) + (.3)1
(.7) + (.3)2
(.7) = 0.973 .</span>
Answer:
13
Step-by-step explanation:
5, 12, 13, 19, 24 is already in least to greatest so all we have to do is select the middle number. Since there is an odd number we don't need to calculate any means.
:)