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Keith_Richards [23]
3 years ago
9

Kercise - 4.3

Mathematics
1 answer:
dsp733 years ago
4 0

Answer:

Aline which is parallel to y-axis is x=a

(i) Here, x=3

Hence, the equation of line parallel to y - axis is at a distance of 3 units to the right is x−3=0

(ii) Here, x=−2

Hence, the equation of the parallel to y- axis at a distance of 2 units to the left is x+2=0

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Solve 11x + 2 = 68.
lys-0071 [83]
11x+2=68
      -2   -2

11x=66
  /11   /11

X=6
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HELPPP <br> what is the value of 6n-2 when n=3?<br><br><br> I BEG
ivann1987 [24]

Answer:

16

Step-by-step explanation:

If n = 3, just put the number 3 instead of n.

So:

6n-2 = 6 * 3 - 2 = 18 - 2 = 16

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-2 square root 20- square root 125
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Answer:-5.93958251....

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In rectangle DATE, the diagonals DT and AE intersect as S. If LaTeX: AE=40 A E = 40 and LaTeX: ST=x+5 S T = x + 5 , find the val
svetoff [14.1K]
For this case we have the following diagonals:
 AE = 40
 ST = x + 5
 The intersection of the diagonals occurs when:
 AE = ST
 Therefore, matching we have:
 40 = x + 5
 Clearing x we have:
 x = 40-5
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 Answer:
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3 years ago
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Jithu is curating Christmas hampers for his neighbours.
iren2701 [21]

1 hamper box, curated by Jithu can be contained 5 cupcakes.

<h3>Calculation:</h3>

The total amount of cupcakes =665 nos.

Jithu wants to create a gift box, each of which contains 6 cupcakes.

We have to see first, whether 665 could be equally distributed or not.

Hence, 665/6= 110.84 unit

It is seen that the number is in a fraction.so, It can be said that 665 cakes cannot be equally distributed to each gift pack carrying 6 cakes.

Hence, 110*6=660 cupcakes.

∴665-660= 5 cupcakes in one box

So, it is concluded that Jithu could be prepared 110 gift boxes containing 6 cakes each & 1 box containing 5 cupcakes.

Learn more about cake-related problems:

brainly.com/question/25225029?referrer=searchResults

#SPJ10

8 0
2 years ago
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