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3 years ago

Kercise - 4.3

Mathematics

1 answer:

dsp733 years ago

4 0

Answer:

Aline which is parallel to y-axis is x=a

(i) Here, x=3

Hence, the equation of line parallel to y - axis is at a distance of 3 units to the right is x−3=0

(ii) Here, x=−2

Hence, the equation of the parallel to y- axis at a distance of 2 units to the left is x+2=0

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I could use your help here

Norma-Jean [14]

Answer:

-1

Step-by-step explanation:

i= -1^(1/2)

= -1^(1/2 x 34)

= -1^(17)

= -1

3 0

3 years ago

What is the name of the place value of 9 in 199

Sliva [168]

The name of place value of 9 in 199 is ones.

The second 9 has a value of tens.

The number 1 has a place value of hundreds.

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3 years ago

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Is the unit price of cantaloupe is 0.65 per ounce in Sally pays $1.95 for a cantaloupe how many pounds did she have her cantalou

Bumek [7]

So the cantaloupe she has is 3 ounces as 195 / 65 = 3 , and 3 ounces is equal to 0.1875 pounds as there are 16 ounces to a pound

4 0

3 years ago

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Let represent the number of tires with low air pressure on a randomly chosen car. The probability distribution of is as follows.

Sindrei [870]

Answer:

a) $P(X=3) = 0.1$

b) $P(X\geq 3) =1-P(X$

And replacing we got:

$P(X \geq 3) = 1- [0.2+0.3+0.1]= 0.4$

c) $P(X=4) = 0.3$

d) $P(X=0) = 0.2$

e) $E(X) =0*0.2 +1*0.3+2*0.1 +3*0.1 +4*0.3= 2$

f) $E(X^2)= \sum_{i=1}^n X^2_i P(X_i)$

And replacing we got:

$E(X^2) =0^2*0.2 +1^2*0.3+2^2*0.1 +3^2*0.1 +4^2*0.3= 6.4$

And the variance would be:

$Var(X0 =E(X^2)- [E(X)]^2 = 6.4 -(2^2)= 2.4$

And the deviation:

$\sigma =\sqrt{2.4} = 1.549$

Step-by-step explanation:

We have the following distribution

x 0 1 2 3 4

P(x) 0.2 0.3 0.1 0.1 0.3

Part a

For this case:

$P(X=3) = 0.1$

Part b

We want this probability:

$P(X\geq 3) =1-P(X$

And replacing we got:

$P(X \geq 3) = 1- [0.2+0.3+0.1]= 0.4$

Part c

For this case we want this probability:

$P(X=4) = 0.3$

Part d

$P(X=0) = 0.2$

Part e

We can find the mean with this formula:

$E(X)= \sum_{i=1}^n X_i P(X_i)$

And replacing we got:

$E(X) =0*0.2 +1*0.3+2*0.1 +3*0.1 +4*0.3= 2$

Part f

We can find the second moment with this formula

$E(X^2)= \sum_{i=1}^n X^2_i P(X_i)$

And replacing we got:

$E(X^2) =0^2*0.2 +1^2*0.3+2^2*0.1 +3^2*0.1 +4^2*0.3= 6.4$

And the variance would be:

$Var(X0 =E(X^2)- [E(X)]^2 = 6.4 -(2^2)= 2.4$

And the deviation:

$\sigma =\sqrt{2.4} = 1.549$

4 0

3 years ago

Find w. A. 8.9 B. 0.05 C. 0.08 D. 5.2

enyata [817]

Answer:

Step-by-step explanation:

Measure of angle V = 180 - 62 - 36 = 82 degrees

So by the law of sines, 10/sin(82 deg) = w/sin(62 deg)

w = [10sin(62)]/sin(82)

from here just plug this into a calculator

4 0

2 years ago