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3 years ago

Your boss bought a new printer with a USB 3.0 port, and it came with a USB 3.0 cable. Your boss asks you:

Computers and Technology

2 answers:

postnew [5]3 years ago

8 0

Answer:

Will the printer work when I connect the printer's USB cable into a USB 2.0 port on my computer:

b. Yes, but at the USB 2.0 speed.

Explanation:

The option a is not correct as we can use 2.0 port also for this purpose but not only 3.0.
The option b is correct as we can use 2.0 USB Port for 3.0 USB but the speed will remain that of 2.0 USB.
The option c is incorrect as because the speed is dependent on the speed of port.
The option d is incorrect as because USB can have speed of 2.0 or 3.0 depending upon the port and USB but can't have 1.1 speed.

stepladder [879]3 years ago

6 0

Answer:

Yes, but at the USB 2.0 speed

Explanation:

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tekilochka [14]

It’s A !!!!!!!!! Just did it

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3 years ago

There exists a data type Date with member function Increment that increments the current Date object by one. The ++ operator is

nalin [4]

Answer:

Date Date::operator++( int )

{

Date temp = *this;

Increment();

return temp;

}

Explanation:

Of options 1 through 4, only option 4 correctly implement the post increment of the ++ operator.

Interpreting each line of option for and comparing it to other options

Line 1: Date Date::operator++( int )

This declares the data type and its ++ operator

This is same for all options

Line 2: The Date type needs to be declared

In option 4, it was declared correctly as Date temp = *this; using a pointer variable *this.

Here, option 2 is removed from the list of possible options.

Comparing other options

Line 3: The member increment option needs to be declared after the declaration of the date type variable.

This is correctly declared as Increment(); in option 4

Here, option 3 is removed from the list of possible options.

Comparing other options

Line 4: The value declared variable temp needs to be returned the way it was declared (without pointer indicator)

Hence, option 4 is best appropriate

3 0

3 years ago

Imagine that you are a professional white hat hacker, testing a company’s system to make sure they are ready for attacks. What m

liberstina [14]

Answer:

A white hat hacker, or ethical hacker, uses penetration testing techniques to test an organization's information technology

Explanation:

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2 years ago

What is impact of Internet<br> in our lives

NeTakaya

Answer:

The Internet has changed business, education, government, healthcare, and even the ways in which we interact with our loved ones—it has become one of the key drivers of social evolution. The changes in social communication are of particular significance.

7 0

3 years ago

Design and implement a class dayType that implements the day of the week in a program. The class dayType should store the day, s

Afina-wow [57]

The code is implemented based on the given operations.

Explanation:

#include <iostream>

#include <string>

using namespace std;

class dayType

{ private:

string day[7];

string presentDay;

int numofDays;

public:

void setDay(string freshDay);

void printDay() const;

int showDay(int &day);

int nextDay(int day);

int prevDay(int day) const;

int calcDay(int day, int numofDays);

dayType()

{

day[0] = "Sunday";

day[1] = "Monday";

day[2] = "Tuesday";

day[3] = "Wednesday";

day[4] = "Thursday";

day[5] = "Friday";

day[6] = "Saturday";

presentDay = day[0];

numofDays = 0;

};

~dayType();

};

#endif

#include "dayType.h"

void dayType::setDay(string freshDay)

{

presentDay = freshDay;

}

void dayType::printDay()

{

cout << "Day chosen is " << presentDay << endl;

}

int dayType::showDay(int& day)

{

return day;

}

int dayType::nextDay(int day)

{

day = day++;

if (day > 6)

day = day % 7;

switch (day)

{

case 0: cout << "The successive day is Sunday";

break;

case 1: cout << "The successive day is Monday";

break;

case 2: cout << "The successive day is Tuesday";

break;

case 3: cout << "The successive day is Wednesday";

break;

case 4: cout << "The successive day is Thursday";

break;

case 5: cout << "The successive day is Friday";

break;

case 6: cout << "The successive day is Saturday";

break;

}

cout << endl;

return day;

}

int dayType::prevDay(int day)

{

day = day--;

switch (day)

{

case -1: cout << "The before day is Saturday.";

break;

case 0: cout << "The before day is Saturday.";

break;

case 1: cout << "The before day is Saturday.";

break;

case 2: cout << "The before day is Saturday.";

break;

case 3: cout << "The before day is Saturday.";

break;

case 4: cout << "The before day is Saturday.";

break;

case 5: cout << "The before day is Saturday.";

break;

default: cout << "The before day is Saturday.";

}

cout << endl;

return day;

}

int dayType::calcDay(int addDays, int numofDays)

{

addDay = addDays + numofDays;

if (addDay > 6)

addDay = addDay % 7;

switch(addDay)

{

case 0: cout << "The processed day is Sunday.";

break;

case 1: cout << "The processedday is Monday.";

break;

case 2: cout << "The processedday is Tuesday.";

break;

case 3: cout << "The processedday is Wednesday.";

break;

case 4: cout << "The processedday is Thursday.";

break;

case 5: cout << "The processedday is Friday.";

break;

case 6: cout << "The processedday is Saturday.";

break;

default: cout << "Not valid choice.";

}

cout << endl;

return addDays;

}

4 0

3 years ago