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MAVERICK [17]
2 years ago
14

How do I get rid of this little tool bar????

Computers and Technology
1 answer:
Serhud [2]2 years ago
4 0

Answer:

settings>Accessibility>Touch>AssistiveTouch>Turn off

Explanation:

You might be interested in
Input two numbers and print their sum products difference division and remainder​
likoan [24]

\tt n1=int(input("Enter\: first\:no:"))

\tt n2=int(input("Enter\: second\:no:"))

\tt sum=n1+n2

\tt diff=n1-n2

\tt pdt=n1*n2

\tt div=n1//n2

\tt rem=n1\%n2

\tt print("Sum=",sum)

\tt print("Difference=",diff)

\tt print("Product=",pdt)

\tt print ("Division=",div)

\tt print("Remainder=",rem)

Output:-

Enter first no:4

Enter second no:3

Sum=7

Difference=1

Product=12

Division=1

Remainder=1

7 0
2 years ago
What is the name of the function below?<br><br> function go(){<br> alert("hello everybody");<br> }
labwork [276]

Answer:

It’s Java script I think and it makes something say hello everybody

Explanation:

6 0
3 years ago
mapa mental con la explicación de que medios de comunicación y redes sociales intervienen en la construcción de tu identidad​
lisov135 [29]

Answer:

este presente yo cuando me pidieron eso

5 0
3 years ago
Write a function in python that computes and returns the sum of the digits for any integer that is between 1 and 999, inclusive.
DanielleElmas [232]

Answer:

def sum_digits(number):

   total = 0

   if 1 <= number <= 999:

       while number > 0:

           r = int (number % 10)

           total +=r

           number /= 10

   else:

       return -1

   return total

   

print(sum_digits(658))

Explanation:

Write a function named sum_digits that takes one parameter, number

Check if the number is between 1 and 999. If it is, create a while loop that iterates until number is greater than 0. Get the last digit of the number using mudulo and add it to the total. Then, divide the number by 10 to move to the next digit. This process will continue until the number is equal to 0.

If the number is not in the given range, return -1, indicating invalid range.

Call the function and print the result

3 0
3 years ago
Given an input array of strings (characters) s, pick out the second column of data and convert it into a column vector of data.
hodyreva [135]

Answer:

Consider the following code.

Explanation:

save the following code in read_and_interp.m

 

function X = read_and_interp(s)

[m, n] = size(s);

X = zeros(m, 1);

for i = 1:m

if(str2num(s(i, 2:5)) == 9999)

% compute value based on previous and next entries in s array

% s(i, 2:5) retrieves columns 2-5 in ith row

X(i,1) = (str2num(s(i-1 ,2:5)) + str2num(s(i+1,2:5)))/2;

else

X(i,1) = str2num(s(i,2:5));

end

end

end

======================

Now you can use teh function as shown below

s = [ 'A' '0096' ; 'B' '0114' ; 'C' '9999' ; 'D' '0105' ; 'E' '0112' ];

read_and_interp(s)

output

ans =

96.000

114.000

109.500

105.000

112.000

7 0
3 years ago
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