6>4-2x<4
so therefor (4x-2) must be less than 6 and less than 4
it must be
6>4-2x and 4<4-2x
find the intersection
6>4-2x
add 2x to both sides
6+2x>4
subtract 6
2x>-2
divide by 2
x>-1
4>4-2x
add 2x
4+2x>4
subtract 4
2x>0
x>0
so we have
x>0
and x>-1
the range of x>-1 includes most of x>0 so the answer is
x>-1
Answer:
18
Step-by-step explanation:
hello,
as this is a parallelogram we can write that BE = DE so
15x + 4 = 9x + 6
<=> 15x - 9x + 4 = 6
<=> 6x = 6 - 4 = 2
<=> x = 2/6 = 1/3
so BE = DE = 15/3+4=5+4=9
so BD = BE + DE = 9 + 9 = 18
the correct answer is 18
hope this helps
I really hate these algebra problems pretending to be geometry.
Anyway angles B and D are congruent in a parallelogram. Geometry part done.
4n - 2 = 2n + 32
2n = 34
n = 17
Answer: 17, which is the 3rd choice
Answer:70
Step-by-step explanation:
10^2 =100
-2(10+15) = -2(15)=-30
100-30= 70