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34kurt
3 years ago
13

Can someone please help me with this plz only on 13

Mathematics
1 answer:
BaLLatris [955]3 years ago
4 0

Answer:

2/9

Step-by-step explanation:

To determine the fraction of students that walk to school, take the fraction of students that do not ride the bus and multiply by the fraction that walk

6/15* 5/9

Simplify the fractions

6/15 Divide the top and bottom by 3

2/5

2/5 * 5/9 = 2/9

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ASAP!! Please help me. I will not accept nonsense answers, but will mark as BRAINLIEST if you answer is correctly with solutions
Elina [12.6K]

Answer:

\boxed{3x-5y}

Step-by-step explanation:

=> 9x^2-25y^2

Let's factor it out

=> (3x^2)-(5y)^2

Using Formula a^2-b^2 = (a+b)(a-b)

=> (3x-5y)(3x+5y)

So, (3x-5y) is one of the factor of it!

3 0
3 years ago
Identify the initial amount a and the growth factor b in the exponential function.
Inessa05 [86]

Answer:

a = 14, b = 2

Step-by-step explanation:

the initial amount was 14

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7 0
3 years ago
Please help quickly <br><br> AB=AD and BC=DC<br> x=?
Arisa [49]

Answer:

x = 110

Step-by-step explanation:

measure of abd is 35, meaning adb is also 35.

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=> x + 35 + 35 = 180

=> x + 70 = 180

=> x = 180-70

=> x = 110

110 degrees is the value of x.  

8 0
2 years ago
I need help can someone tell me how to do this plz
KiRa [710]

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4 0
2 years ago
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Solve the following integral.<br><br> <img src="https://tex.z-dn.net/?f=%5Cint4x%5Ccos%282-3x%29dx" id="TexFormula1" title="\int
bagirrra123 [75]

Hi there!

\boxed{-\frac{4x}{3}sin(2-3x) + \frac{4}{9}cos(2-3x) + C}

To find the indefinite integral, we must integrate by parts.

Let "u" be the expression most easily differentiated, and "dv" the remaining expression. Take the derivative of "u" and the integral of "dv":

u = 4x

du = 4

dv = cos(2 - 3x)

v = 1/3sin(2 - 3x)

Write into the format:

∫udv = uv - ∫vdu

Thus, utilize the solved for expressions above:

4x · (-1/3sin(2 - 3x)) -∫ 4(1/3sin(2 - 3x))dx

Simplify:

-4x/3 sin(2 - 3x) - ∫ 4/3sin(2 - 3x)dx

Integrate the integral:

∫4/3(sin(2 - 3x)dx

u = 2 - 3x

du = -3dx ⇒ -1/3du = dx

-1/3∫ 4/3(sin(2 - 3x)dx ⇒ -4/9cos(2 - 3x) + C

Combine:

-\frac{4x}{3}sin(2-3x) + \frac{4}{9}cos(2-3x) + C

7 0
2 years ago
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