In general: <span>(a - b)^3 = a^3 - 3 a^2b + 3 a b^2 - b<span>^3
(4x-2y)^3 = </span></span>(4x)^3 - 3 (4x)^2(2y) + 3 (4x) (2y)^2 - (2y)^3
So here's how to do it,
slope intercept form is y=mx+b
m is the slope, b is the y- intercept, X is your unknown variable.
you need to solve to get y by its self to get your slope.
for perpendicular lines flip the slope
ex 1, smy=2x+6 --- slope of a perpendicular line will be 1/2
ex 2, y=3/2+8 ---8 perpendicular lien would have a slope of 2/3
parallel lines have the same slope so any equation with with the same slope will be parallel if it has the same degree.
ex. y=2x+14 is parallel to y= 2x+56
slope can be found using the following formula if you have two sets of points on the same line
m= y2-y1 ÷ X2 - X1
Answer:
c
Step-by-step explanation:
because you add up all the days then you get the total
Let the side of the garden alone (without walkway) be x.
Then the area of the garden alone is x^2.
The walkway is made up as follows:
1) four rectangles of width 2 feet and length x, and
2) four squares, each of area 2^2 square feet.
The total walkway area is thus x^2 + 4(2^2) + 4(x*2).
We want to find the dimensions of the garden. To do this, we need to find the value of x.
Let's sum up the garden dimensions and the walkway dimensions:
x^2 + 4(2^2) + 4(x*2) = 196 sq ft
x^2 + 16 + 8x = 196 sq ft
x^2 + 8x - 180 = 0
(x-10(x+18) = 0
x=10 or x=-18. We must discard x=-18, since the side length can't be negative. We are left with x = 10 feet.
The garden dimensions are (10 feet)^2, or 100 square feet.
