Answer: 13.2%
Explanation:
Given data:
No of stores in the market = 5000
No. of store owners = 2000.
Allison charges = $8/month
Sam charges = $8/month.
Solution:
The market penetration rate would be calculated based on potential customers.
Using our general formula,
Market penetration=Numbers of customers who purchased Allison derived sales and Sam derived sales /Total potential population
Where,
Total potential population=1,500
•Allison derived sales = 129 customers
•Sam derived sales = 69 customers
•Numbers of customers who purchased Allison derived sales and Sam derived sales=129 customers+ 69 customers
•Numbers of customers who purchased Allison derived sales and Sam derived sales =198 customers
Let’s input this into our general formula.
Market penetration
= 169 customers/1,500
= 0.132*100
= 13.2%
The market penetration rate based on potential customers is 13.2%
Answer:
Following are the solution to the given question:
Explanation:
Revenue before continuing business 585000
less:income tax -187000
Continuous business revenue 398,000
Operations stopped
Loss of non-compliance -75000
Less: Applicable drop in income tax from 25500 - 49500
net sales 348500
Popular inventory per share
Continued operating revenue ![[\frac{398000}{100000}] \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \$3.98](https://tex.z-dn.net/?f=%5B%5Cfrac%7B398000%7D%7B100000%7D%5D%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%243.98)
Losses on disrupted businesses, tax net![[\frac{-49500}{100000}]](https://tex.z-dn.net/?f=%5B%5Cfrac%7B-49500%7D%7B100000%7D%5D)
Net-0.495
Net profits ![[\frac{348500}{100000}] \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 3.485](https://tex.z-dn.net/?f=%5B%5Cfrac%7B348500%7D%7B100000%7D%5D%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%20%5C%203.485)
Answer:
c. Optimum replacement interval (ORI)
Explanation:
Optimum replacement interval used to estimate the most cost effective time to replace an asset on the basis of their replacement cost.
There needs to be a balance between the replacement cost and the value that is being lost by changing the asset.
The useful value must be low to justify replacement cost.
For example if the cost of maintaining a machine has increased a lot as a result of wear and tear, it will be more cost effective to make a replacement in order to minimise cost and increase efficiency
Answer:
Let suppose the value of property is 100 dollars currently.
The price of a certain property increased by 10% in the first year, means the value of property at this point is (100 *1.1) 110 dollars.
In the second year the value of property decreases by 20% mean the value of property at this point is (110*0.80) 88 dollars, that is 80% of previous value determine.
In the third year the value of property increases by 25% mean the value of property at this point is (88*1.25) 110 dollars that is 25% more than previous value determine.
So in second year the value in dollars is 88 dollars.
