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3 years ago

Write equivalent expression of 15g+20h

Mathematics

1 answer:

JulijaS [17]3 years ago

3 0

In this question, you're trying to make an equivalent expression.

Your expression should be similar to:

15g + 20h

One of the best ways to make an equivalent expression is by using the distributive property.

You would see they're both divisible by 5, so we would be using 5 in our expression.

Your expression should look like this:

5(3g + 4h)

Answer:

5(3g + 4h)

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I NEED A EXPLAINATION

astraxan [27]

2.54,2,-1.79,-4

Step-by-step explanation:

gretest is 2.54 because 2.54 is nearer to 3so it is greatest. then 2 is smaller than 2.54 and then -1.74 and -4 because the number which is greater in negative is the most smallest number.

for , another example -1 is greater than-100.

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3 years ago

WILL GIVE 20 POINTS

Oksanka [162]

Answer:

The answer is B

Step-by-step explanation:

75 + x = 90

First, Virginia had to write an equation to solve for x.

75 - 75 + x = 90 - 75

Second, Virginia used the subtraction property of equality to isolate x.

x = 15

Third, "x = 15" was the answer Virginia got after subtracting 90 and 75.

75 + 15 = 90

Finally, she had to verify her answer

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3 years ago

Emma works on an ice cream truck. She has lots of ice creams in the cooler. On Friday, she gave out 58 ice creams. Now she has 7

damaskus [11]

Answer:

She had a total of 131 before she sold anything

Step-by-step explanation:

Add 58 and 73

4 0

3 years ago

In a recent year, Washington State public school students taking a mathematics assessment test had a mean score of 276.1 and a s

Oksi-84 [34.3K]

Answer:

a) $\mu_{\bar x} =\mu = 276.1$

$\sigma_{\bar x} =\frac{\sigma}{\sqrt{n}}=\frac{34.4}{\sqrt{64}}=4.3$

b) From the central limit theorem we know that the distribution for the sample mean $\bar X$ is given by:

$\bar X \sim N(\mu=276.1, \frac{\sigma}{\sqrt{n}}=4.3)$

c) $P(\bar X \geq 285)=P(Z\geq \frac{285-276.1}{4.3}=2.070)$

$P(Z\geq2.070)=1-P(Z$

Step-by-step explanation:

Let X the random variable the represent the scores for the test analyzed. We know that:

$\mu=E(X) = 276.1 , \sigma=Sd(X) = 34.4$

And we select a sample size of 64.

The central limit theorem states that "if we have a population with mean μ and standard deviation σ and take sufficiently large random samples from the population with replacement, then the distribution of the sample means will be approximately normally distributed. This will hold true regardless of whether the source population is normal or skewed, provided the sample size is sufficiently large".

Part a

For this case the mean and standard error for the sample mean would be given by:

$\mu_{\bar x} =\mu = 276.1$

$\sigma_{\bar x} =\frac{\sigma}{\sqrt{n}}=\frac{34.4}{\sqrt{64}}=4.3$

Part b

From the central limit theorem we know that the distribution for the sample mean $\bar X$ is given by:

$\bar X \sim N(\mu=276.1, \frac{\sigma}{\sqrt{n}}=4.3)$

Part c

For this case we want this probability:

$P(\bar X \geq 285)$

And we can use the z score defined as:

$z=\frac{\bar x -\mu}{\sigma_{\bar x}}$

And using this we got:

$P(\bar X \geq 285)=P(Z\geq \frac{285-276.1}{4.3}=2.070)$

And using a calculator, excel or the normal standard table we have that:

$P(Z\geq2.070)=1-P(Z$

8 0

3 years ago

Please help me. Factor. 5x^+23x+26

Alexus [3.1K]

20,897,614 solved | 1,346 online

Skip Ad 
 5x2-23x=-26 Two solutions were found : x = 2 x = 13/5 = 2.600

Rearrange:

Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation :

5*x^2-23*x-(-26)=0

Step by step solution :Skip Ad
 Step 1 :Equation at the end of step 1 : (5x2 - 23x) - -26 = 0 Step 2 :Trying to factor by splitting the middle term

2.1 Factoring 5x2-23x+26

The first term is, 5x2 its coefficient is 5 .
The middle term is, -23x its coefficient is -23 .
The last term, "the constant", is +26 

Step-1 : Multiply the coefficient of the first term by the constant 5 • 26 = 130

Step-2 : Find two factors of 130 whose sum equals the coefficient of the middle term, which is -23 .

-130 + -1 = -131 
 -65 + -2 = -67 
 -26 + -5 = -31 
 -13 + -10 = -23 That's it

4 0

3 years ago

Write equivalent expression of 15g+20h​

Write equivalent expression of 15g+20h