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3 years ago

The value of the square root of -16 is not -4 because

Mathematics

2 answers:

Nady [450]3 years ago

4 0

Answer:

negative numbers can't have a square root it would have to be imaginary

Step-by-step explanation:

inysia [295]3 years ago

3 0

hi,

there is no negative number in R that have a square root as : -a * -a = +a²

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schepotkina [342]

X+2 Hope this helps!

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2 years ago

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Softa [21]

Answer:

CAB = 30.71 BCA = 90 ABC = 59.29

Step-by-step explanation:

BCA = 90

9x + 6 + 5x = 90

14 x = 90-6 = 84

x = 43/7

(43/7 ) * 5 = 30.71

90 - 30.71 = 59.29

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2 years ago

The ratio of boys to girls in mr.Smiths class is 3:2 which statement is correct circle that all apply

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3 years ago

Find the perimeter of a rectangle with sides (3x-5) and (-2x+10)

Vinil7 [7]

2(3x-5) + 2(-2x+10)
6x-10 + -4x+ 20

=2x+ 10

5 0

3 years ago

What is the equation of the line that is perpendicular to the given line and passes through the point (3, 0)?

olga2289 [7]

Step $1$

Find the slope of the given line

Let

$A(-3,2)\ B(2,-1)$

slope mAB is equal to

$mAB=\frac{(y2-y1)}{(x2-x1)} \\ \\ mAB=\frac{(-1-2)}{(2+3)} \\ \\ mAB=-\frac{3}{5}$

Step $2$

Find the slope of the line that is perpendicular to the given line

Let

CD ------> the line that is perpendicular to the given line

we know that

If two lines are perpendicular, then the product of their slopes is equal to $-1$

$mAB*mCD=-1\\ mAB=-\frac{3}{5} \\ mCD=-\frac{1}{mAB} \\ mCD=\frac{5}{3}$

Step $3$

Find the equation of the line with mCD and the point (3,0)

we know that

the equation of the line in the form point-slope is equal to

$y-y1=m(x-x1)\\\\ y-0=\frac{5}{3} *(x-3)\\\\ y=\frac{5}{3} x-5$

Multiply by $3$ both sides

$3y=5x-15$

$5x-3y=15$

therefore

the answer is

the equation of the line that is perpendicular to the given line is the equation $5x-3y=15$

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2 years ago

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