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sergey [27]
3 years ago
6

Below is the data on the percentage of 25- to 34-year-olds in each of the 50 states and the District of Columbia, listed in alph

abetical order, who had some type of postsecondary degree as of 2010: 31.5 32.9 33.0 28.6 37.2 43.3 45.9 37.2 68.8 36.2 35.5 31.5 32.9 33.0 28.6 37.2 43.3 45.9 37.2 68.8 36.2 35.5 40.5 37.2 45.3 36.1 45.5 42.3 33.3 30.3 37.2 45.5 54.3 37.2 49.8 32.1 39.3 40.3 44.2 28.4 46.0 47.2 32.8 32.2 38.5 44.5 44.6 40.9 29.5 41.3 35.4 a. Identify all the outliers. b. Construct a stem-and-leaf plot. c. Construct a relative frequency
Mathematics
1 answer:
NARA [144]3 years ago
7 0

Answer:

Step-by-step explanation:

Given the following data:

31.5 32.9 33.0 28.6 37.2 43.3 45.9 37.2 68.8 36.2 35.5 31.5 32.9 33.0 28.6 37.2 43.3 45.9 37.2 68.8 36.2 35.5 40.5 37.2 45.3 36.1 45.5 42.3 33.3 30.3 37.2 45.5 54.3 37.2 49.8 32.1 39.3 40.3 44.2 28.4 46.0 47.2 32.8 32.2 38.5 44.5 44.6 40.9 29.5 41.3 35.4

Value ___frequency____relative frequency %

28.4_______1 __________1. 96

28.6_______2__________3.92

29.5_______1___________1.96

30.3_______1___________1.96

31.5_______2___________3.92

32.1_______1____________1.96

32.2_______1___________1.96

32.8_______1___________1.96

32.9_______2___________3.92

33________2___________3.92

33.3_______1___________1.96

35.4_______1___________1.96

35.5_______2___________3.92

36.1________1___________1.96

36.2_______2___________3.92

37.2_______7___________13.73

38.5_______1____________1.96

39.3_______1____________1.96

40.3_______1____________1.96

40.5_______1____________ 1.96

40.9_______1____________1.96

41.3_______1 ____________1.96

42.3______1_____________1.96

43.3______2____________ 3.92

44.2______1 _____________1.96

44.5______1 _____________1.96

44.6_____ 1 ______________1.96

45.3_____1 _______1.96

45.5_____2 ______3.92

45.9_____2 ______3.92

46______1 _______1.96

47.2_____1 _______1.96

49.8_____1 _______1.96

54.3____1________1.96

68.8____2________3.92

Lower outlier = Q1 - (1.5 × IQR)

Upper outlier = Q3 + (1.5 × IQR)

IQR = Interquartile range ;

Q1 = 1/4(n+1)th term

Q3 = 3/4(n+1)th term

IQR = Q3 - Q1

n = number of observations = 51

Q1 = (51 + 1)/4= 52/4 = 13 th term = 33

Q3 = 3(51 + 1) /4 = 156/4 = 39th term = 44.5

IQR = 44.5 - 33 = 11.5

LOWER OUTLIER = 33 - (1.5*11.5) = 33 - 17.25 = entries < 15.75

UPPER OUTLIER = 44.5 + (1.5*11.5) = 44.5 + 17.25 = 61.75

Entries > 61.75

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ASHA 777 [7]

The question is incomplete. The complete question is as follows.

Juan, Carlos and Maria went to the museum. The entrance ticket cost $5 per person, but, as they are students, there is a discount of $1 per ticket. After, they bought: 3 combos of chicken and fries costing $4 each; 3 bottles of water costing $1 each; 3 vanilla cookies costing $1 each; How much money each student paid if they divided the costs in equal amount?

Answer: $10

Step-by-step explanation: As each students split the bill in equal parts, to find how much they spent, we can calculate how much one of the three spent.

For ticket: 5 - 1 (because of the students discount) = $4

Each combo of chicken and fries cost $4, so: combo = $4

Each bottle of water costs $1, so: water = $1

and each vanilla cookie costs $1: cookie = $1

Total spent is:

T = 4+4+1+1

T = 10

Each student spent a total of $10 for this outing.

7 0
3 years ago
For every 10 cans John collected for recycling, he earned 9 cents. After he collects 80 cans, how much money would he have earne
andre [41]

Answer:

72 cents

Step-by-step explanation:

10(1) = 9 cans so 80(8) = 72 cans.

5 0
3 years ago
A boy had 4 marbles and lost one. How many marbles does he have now?
AVprozaik [17]

Answer:

3

Step-by-step explanation:

4-1

6 0
2 years ago
( – 1, – 5) 7x+2y=13, 4x+4y=14
serious [3.7K]

Answer:

{x,y} = {6/5,23/10}

Step-by-step explanation:

 [1]    7x + 2y = 13

  [2]    4x + 4y = 14  <---------- linear equations given

Graphic Representation of the Equations : PICTURE
2y + 7x = 13        4y + 4x = 14  

Solve by Substitution :

// Solve equation [2] for the variable  y

[2]    4y = -4x + 14

[2]    y = -x + 7/2

// Plug this in for variable  y  in equation [1]

  [1]    7x + 2•(-x +7/2) = 13

  [1]    5x = 6

// Solve equation [1] for the variable  x

  [1]    5x = 6

  [1]    x = 6/5

// By now we know this much :

   x = 6/5

   y = -x+7/2

// Use the  x  value to solve for  y

   y = -(6/5)+7/2 = 23/10

// Plug this in for variable  y  in equation [1]

 [1]    7x + 2•(-x +7/2) = 13

  [1]    5x = 6

// Solve equation [1] for the variable  x

 [1]    5x = 6

[1]    x = 6/5

// By now we know this much :

   x = 6/5

   y = -x+7/2

// Use the  x  value to solve for  y

  y = -(6/5)+7/2 = 23/10

4 0
2 years ago
Hey can someone help:)?​
Zolol [24]
I think it’s the first one
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