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otez555 [7]
1 year ago
13

Kelsey had $65 to spend on books. Each book cost $5.50, and there was a $7.50 fee for shipping. She let b equal the number of bo

oks she can purchase and wrote the inequality 5.50 b + 7.5 less-than 65 to represent the situation. Which statements describe the reasoning used to determine if Kelsey’s inequality is correct? Select two options. The inequality symbol is correct because she must spend less than $65. The inequality symbol is incorrect because she can spend up to and including $65. The expression 5.50b + 7.5 is correct because $5.50 per book is 5.50b and that is added to the shipping fee of $7.50 to determine the total purchase price. The expression 5.50b + 7.5 is incorrect because $5.50 per book and $7.50 should be combined to $9.50b to determine the total purchase price. The inequality symbol is correct because she cannot spend more than $65. PLS NEED ASAP!!
Mathematics
1 answer:
xeze [42]1 year ago
3 0

Answer: Kelsey had $65 to spend on books. Each book cost $5.50, and there was a $7.50 fee for shipping. She let b equal the number of books she can purchase

Step-by-step explanation:

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2<br>If A=<br>4 3<br>find A1 using<br>elementary row operations.​
MA_775_DIABLO [31]

Answer:   A^{-1}=\left[\begin{array}{cc}\frac{3}{2}&-\frac{1}{2}\\-2&1\end{array}\right]

<u>Step-by-step explanation:</u>

                  \left[\begin{array}{cc}2&1\\4&3\end{array}\right]=\left[\begin{array}{cc}1&0\\0&1\end{array}\right]

\dfrac{1}{2}Row\ 1\rightarrow\left[\begin{array}{cc}1&\frac{1}{2}\\4&3\end{array}\right]=\left[\begin{array}{cc}\frac{1}{2}&0\\0&1\end{array}\right]

Row\ 2 -4 \ Row\ 1\rightarrow \left[\begin{array}{cc}1&\frac{1}{2}\\0&1\end{array}\right]=\left[\begin{array}{cc}\frac{1}{2}&0\\-2&1\end{array}\right]

Row\ 1-\dfrac{1}{2}\ Row\ 2 \rightarrow \left[\begin{array}{cc}1&0\\0&1\end{array}\right]=\left[\begin{array}{cc}\frac{3}{2}&-\frac{1}{2}\\-2&1\end{array}\right]

5 0
3 years ago
Anyone know the answer to to this algebra question?
liraira [26]

Answer:

a=1

b= 1/16

c= 1/256

d= 1

e= 4/9

f= 16/81

Step-by-step explanation:

Plug in the values of X on the left side of the table into the function on the right side of the table. Remember that negative exponents mean the number is under a fraction. 4^-0 is like saying one over 4^0.

For the blue table, because the numbers are already in a fraction and in parentheses, you apply the exponent to each number individually.

7 0
3 years ago
What is Yasmeen's annual salary if her salary per fortnight is $1610?<br><br><br><br>​
Oksi-84 [34.3K]

Answer:

$41,860.

Step-by-step explanation:

Weekly salary = 1610 / 2 = $805.

There are 52 weeks in a year so her annual salary

= 805 * 52 = $41,860.

8 0
3 years ago
Help pls itS BEEN 2 HOURS LUV U &lt;3
nataly862011 [7]

Step-by-step explanation:

Hey there!

The equation of a circle which passes through any point having centre (h,k) is;

( {x - h)}^{2}  + ( {y - k)}^{2}  =  {r}^{2}

In first blank ( x-_ ) keep "-2". In second blank (y - _ ) keep "4" and in last blank ( _ ) keep "36".

<em><u>Hope</u></em><em><u> </u></em><em><u>it helps</u></em><em><u>.</u></em><em><u>.</u></em>

7 0
3 years ago
Please help me now ! Thank you
jarptica [38.1K]
First we'll do two basic steps. Step 1 is to subtract 18 from both sides. After that, divide both sides by 2 to get x^2 all by itself. Let's do those two steps now

2x^2+18 = 10
2x^2+18-18 = 10-18 <<--- step 1
2x^2 = -8
(2x^2)/2 = -8/2 <<--- step 2
x^2 = -4

At this point, it should be fairly clear there are no solutions. How can we tell? By remembering that x^2 is never negative as long as x is real. 

Using the rule that negative times negative is a positive value, it is impossible to square a real numbered value and get a negative result. 

For example
2^2 = 2*2 = 4
8^2 = 8*8 = 64
(-10)^2 = (-10)*(-10) = 100
(-14)^2 = (-14)*(-14) = 196

No matter what value we pick, the result is positive. The only exception is that 0^2 = 0 is neither positive nor negative.

So x^2 = -4 has no real solutions. Taking the square root of both sides leads to

x^2 = -4
sqrt(x^2) = sqrt(-4)
|x| = sqrt(4)*sqrt(-1)
|x| = 2*i
x = 2i or x = -2i
which are complex non-real values


5 0
3 years ago
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