Well, remember we can't take the square root of a negative
so we see that we have

so find those values that take sqrt of a negative and restrict hem from the domain
anny value greater than 1 and less than -1
so domain is from -1 to 1, including those numbers
D=[-1,1]
a. D=[-1,1] or from -1 to 1 is domain
b. for a TI-84, go to y-editor then input

for y1
c. for a TI-84, click 2nd then window (gets to tbset) scrol down to set Δx to 0.1, then cilick 2nd again then click graph (to select table) and scroll down till you see that value of y that is the biggest, that value is x=0.7
A. domain is from -1 to 1
B. use your brain or google the instructions for your calulator
C. at x=0.7
Answer:
in the intersection region of all the solution in the system.
Answer:
x(6 + 8x²) or 6x + 8x³.
Step-by-step explanation:
"The square of x" can be represented by x² and 8 times that would be 8 * x² or 8x². The sum of 6 and 8x² can be represented by 6 + x² and the product of x and 6 + x² can be represented by x * (6 + 8x²) or x(6 + 8x²) which simplifies to 6x + 8x³.
The word "times" means you have to multiply.
2 1/5 times 1 3/4 is 3 17/20.
The phrase "how many more" means you have to subtract.
3 17/20 minus 2 1/5 is 1 13/20.
Carson walked her dog 1 13/20 more miles than Claire did.
Sorry for the lazy explanations Imao