Answer:
2.0 seconds
Step-by-step explanation:
<u>Given quadratic functions</u>:

To find the time, in seconds, that the balloons collided at the highest point, <u>substitute</u> one equation into the other equation and rearrange to <u>equal zero</u>:

<u>Factor</u> the quadratic:

Apply the <u>zero-product property</u> to solve for x:


Therefore, the balloons collided at 1 second and 2 seconds.
To find at which time the highest point of collision occured, substitute both values of x into one of the functions:


Therefore, the time, in seconds, that the balloons collided at the highest point is 2.0 seconds.
Learn more about quadratic systems of equations here:
brainly.com/question/27930827
Answer:
The margin of error for the 95% confidence interval used to estimate the population proportion is of 0.0209.
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of
, and a confidence level of
, we have the following confidence interval of proportions.

In which
z is the z-score that has a p-value of
.
The margin of error is of:

In a clinical test with 2161 subjects, 1214 showed improvement from the treatment.
This means that 
95% confidence level
So
, z is the value of Z that has a p-value of
, so
.
Margin of error:



The margin of error for the 95% confidence interval used to estimate the population proportion is of 0.0209.
Answer:
C.
Step-by-step explanation:
Move to the right 2 units,
Move down 2 units.
Solution:
1x +2x -7 =0
3x-7=0
Add 7 To Both Sides Of The Equal Sign Then Divide By 3
Answer:
-2
Step-by-step explanation:
Distribute
2
(
3
+
4
)
+
2
=
4
+
3
{\color{#c92786}{2(3x+4)}}+2=4+3x
2(3x+4)+2=4+3x
6
+
8
+
2
=
4
+
3
{\color{#c92786}{6x+8}}+2=4+3x
6x+8+2=4+3x
2
Add the numbers
6
+
8
+
2
=
4
+
3
6x+{\color{#c92786}{8}}+{\color{#c92786}{2}}=4+3x
6x+8+2=4+3x
6
+
1
0
=
4
+
3
6x+{\color{#c92786}{10}}=4+3x
6x+10=4+3x
3
Rearrange terms
6
+
1
0
=
4
+
3
6x+10={\color{#c92786}{4+3x}}
6x+10=4+3x
6
+
1
0
=
3
+
4
6x+10={\color{#c92786}{3x+4}}
6x+10=3x+4
4
Subtract
1
0
10
10
from both sides of the equation
6
+
1
0
=
3
+
4
6x+10=3x+4
6x+10=3x+4
6
+
1
0
−
1
0
=
3
+
4
−
1
0
6x+10{\color{#c92786}{-10}}=3x+4{\color{#c92786}{-10}}
6x+10−10=3x+4−10
5
Simplify
Subtract the numbers
Subtract the numbers
6
=
3
−
6
6x=3x-6
6x=3x−6
6
Subtract
3
3x
3x
from both sides of the equation
6
=
3
−
6
6x=3x-6
6x=3x−6
6
−
3
=
3
−
6
−
3
6x{\color{#c92786}{-3x}}=3x-6{\color{#c92786}{-3x}}
6x−3x=3x−6−3x
7
Simplify
Combine like terms
Combine like terms
3
=
−
6
3x=-6
3x=−6
8
Divide both sides of the equation by the same term
3
=
−
6
3x=-6
3x=−6
3
3
=
−
6
3
\frac{3x}{{\color{#c92786}{3}}}=\frac{-6}{{\color{#c92786}{3}}}
33x=3−6
9
Simplify
Cancel terms that are in both the numerator and denominator
Divide the numbers
=
−
2