Answer:
53
Step-by-step explanation:
you just need to reflect your lines to find answer.
Answer:
480 students want more field trips.
60 students is 10%.
Step-by-step explanation:
There are 600 students, and 80% want more field trips.
80% of 600 is 0.8*600 = 8*60 = 480 students.
480 students want more field trips.
Answer:
Originally, you will <em>pay</em> $95.75 for the dog.
Step-by-step explanation:
Given:
Maintenance cost of dog after 55 months = $5,468.50
Maintenance cost of dog after 82 months = $8,053.75
To Find:
How much did you pay for the dog originally = ?
Solution:
It is stated that the maintenance cost is same from month to month
Now 82 - 55 = 27 months
For 27 we have paid
$8,053.75 - $5,468.50
$2585.25
But one month the amount paid will be
<h3>
=>95.75</h3>
Part A
Answers:
Mean = 5.7
Standard Deviation = 0.046
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The mean is given to us, which was 5.7, so there's no need to do any work there.
To get the standard deviation of the sample distribution, we divide the given standard deviation s = 0.26 by the square root of the sample size n = 32
So, we get s/sqrt(n) = 0.26/sqrt(32) = 0.0459619 which rounds to 0.046
================================================
Part B
The 95% confidence interval is roughly (3.73, 7.67)
The margin of error expression is z*s/sqrt(n)
The interpretation is that if we generated 100 confidence intervals, then roughly 95% of them will have the mean between 3.73 and 7.67
-----------------------
At 95% confidence, the critical value is z = 1.96 approximately
ME = margin of error
ME = z*s/sqrt(n)
ME = 1.96*5.7/sqrt(32)
ME = 1.974949
The margin of error is roughly 1.974949
The lower and upper boundaries (L and U respectively) are:
L = xbar-ME
L = 5.7-1.974949
L = 3.725051
L = 3.73
and
U = xbar+ME
U = 5.7+1.974949
U = 7.674949
U = 7.67
================================================
Part C
Confidence interval is (5.99, 6.21)
Margin of Error expression is z*s/sqrt(n)
If we generate 100 intervals, then roughly 95 of them will have the mean between 5.99 and 6.21. We are 95% confident that the mean is between those values.
-----------------------
At 95% confidence, the critical value is z = 1.96 approximately
ME = margin of error
ME = z*s/sqrt(n)
ME = 1.96*0.34/sqrt(34)
ME = 0.114286657
The margin of error is roughly 0.114286657
L = lower limit
L = xbar-ME
L = 6.1-0.114286657
L = 5.985713343
L = 5.99
U = upper limit
U = xbar+ME
U = 6.1+0.114286657
U = 6.214286657
U = 6.21
Answer:
120 x 10^3
7 x 10^5
9 x 10^4
Step-by-step explanation:
