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3 years ago

Simplify the expression. Select the best answer from the choices below.

Mathematics

1 answer:

Alik [6]3 years ago

4 0

Answer:

10x-6+y

Step-by-step explanation:

remove parentheses then collect like terms,hope this helped:)

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Car Value: In one year a new car decreased in value by 20%. If it sold for $19,400 when it was new, what was it worth after 1 ye

Phantasy [73]

20% of $19,400 is $3,880
($19,400 / 5 = $3,880)
subtract 20% from the original value
($19,400 - $3,880 = $15,520)
it's now worth $15,520

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3 years ago

Help please with 2 questions. I'll give brainiest!! Both questions PLEASE!

Nadusha1986 [10]

Answer:

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3 years ago

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Please help me. I’ve been stuck on this question forever.

koban [17]

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Step-by-step explanation:

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3 years ago

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A true-false quiz with 10 questions was given to a statistics class. Following is the probability distribution for the score of

disa [49]

Answer:

$E(X)=\sum_{i=1}^n X_i P(X_i)$

And if we use the values obtained we got:

$E(X)=5*0.05 +6*0.15 +7*0.33 +8*0.28+ 9*0.12 +10*0.07=7.48$

For this case this value means that the expected score is about 7.48

Step-by-step explanation:

For this case we assume the following probability distribution:

X 5 6 7 8 9 10

P(X) 0.05 0.15 0.33 0.28 0.12 0.07

First we need to find the expected value (first moment) and the second moment in order to find the variance and then the standard deviation.

In order to calculate the expected value we can use the following formula:

$E(X)=\sum_{i=1}^n X_i P(X_i)$

And if we use the values obtained we got:

$E(X)=5*0.05 +6*0.15 +7*0.33 +8*0.28+ 9*0.12 +10*0.07=7.48$

For this case this value means that the expected score is about 7.48

In order to find the standard deviation we need to find first the second moment, given by :

$E(X^2)=\sum_{i=1}^n X^2_i P(X_i)$

And using the formula we got:

$E(X^2)=(5^2 *0.05)+(6^2 *0.15)+(7^2 *0.33)+(8^2 *0.28)+ (9^2 *0.12 +(10^2 *0.07))=57.46$

Then we can find the variance with the following formula:

$Var(X)=E(X^2)-[E(X)]^2 =57.46-(7.48)^2 =1.5096$

And then the standard deviation would be given by:

$Sd(X)=\sqrt{Var(X)}=\sqrt{1.5096}=1.229$

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3 years ago

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