These numbers would be -5 & 6...
(-5)(6) = -30
-5 + 6 = 1
Answer:
I belive its C not 100%
Step-by-step explanation:
The answer is C. 120
The solution can be derived by the formula 6P3.
6P3 = 6 * 5 * 4 = 120
120 different combinations can be made with the condition.
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Answer:
(a) No the conclusion is not justified.
b. No
c. Two defective circuits in the sample
Step-by-step explanation:
Ans: (a) No the conclusion is not justified. What is important is the percentage population of defectives;
the sample proportion is only an approximation. The population proportion
for the new process may be more than or less than that of the old process. We can decide to pick two hundred samples and discover that the number of defects is greater than the previous process
(b)
.For the defectives, the population proportion for the new process may be 0.12 or more,
although the sample of defectives is just 11 out of 100
(c) Two defective circuits in the sample. This is because the probability of having two defects from the 100n samples is less than having 11 defects
