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3 years ago

Necesito ayudaaaaa pls

Mathematics

1 answer:

ikadub [295]3 years ago

4 0

Answer:

A= 10 $\sqrt{6}$

Hope this helps!

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What are the solutions to the system of equations graphed

sweet-ann [11.9K]

Answer:

The point of intersection between the 2 graphs.

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3 years ago

You are dealt one card from a satndard 52-card deck. Find the probability of being dealt an ace or a 7

ruslelena [56]

Answer:

2/13 or 15.38%

Step-by-step explanation:

Number of Aces in a deck = 4

Number of 7s in a deck = 4

Number of cards in a deck = 52

Probability of A or 7 = (4 Aces + 4 Sevens) / 52 cards 8 cards / 52 cards

This simplifies to 2/13 or 15.38%

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2 years ago

Please help! Correct Answers only!

mafiozo [28]

Answer:

$12000

Step-by-step explanation:

Using the given formula :

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3 years ago

In 1990, California switched from a 6/49 lottery to a 6/53 lottery. Later, the state switched again to a 6/51 lottery. (a) Find

zalisa [80]

Answer:

(a) 9.9321*10^{-11}

(b) 6.0498*10^{-11}

(d) 1.6417 times more probable

Step-by-step explanation:

(a) The probability of winning a 6/49 lottery is given by:

$P = \frac{1}{49*48*47*46*45*44} =9.9321*10^{-11}$

(b) The probability of winning a 6/53 lottery is given by:

$P = \frac{1}{53*52*51*50*49*48} =6.0498*10^{-11}$

(c) The probability of winning a 6/51 lottery is given by:

$P = \frac{1}{51*50*49*48*47*46} =7.7120^{-11}$

(d) The ratio between the probabilities of winning the 6/49 lottery and winning the 6/53 lottery is:

$r=\frac{9.9321*10^{-11}}{6.0498^{-11}}\\r=1.6417$

It is 1.6417 times more probable.

8 0

3 years ago

What is the integral of ∫4x^2 dx

Nataly_w [17]

Answer:

$\boxed{\frac{4}{3} x^3 + c}$

Step-by-step explanation:

$\int\limits {4x^2} \ dx$

$= \frac{4}{3} x^3 + c$

5 0

3 years ago

Read 2 more answers