All categories

3 years ago

Please help me WILL MARK BRAINLYIST

Mathematics

2 answers:

dmitriy555 [2]3 years ago

7 0

Answer:

The correct answer is A

Step-by-step explanation:

just trust me XD

Hope this help :)

yan [13]3 years ago

4 0

The correct answer is
A

when you distribute 5
to the terms in the parentheses, you get -5x-15, and then all you need to do is add x to the second power, and -4x to
the second power, and since -5x 3x to the second power, and -15 aren’t like terms, -3x to the second power -5x-15 is you answer
Hope this helped

You might be interested in

342%<br> What is the fraction equivalent?

love history [14]

How simplified does the fraction need to be ??

8 0

3 years ago

Read 2 more answers

Jamie has 1/10 yard of blue felt and 5/6 yard yard of green felt.

kondor19780726 [428]

Answer:

Jamie has 11/15 yards of Green Felt more than Blue Felt

Step-by-step explanation:

Green felt- Blue felt

= 5/6- 1/10

= 25/30- 3/30 ( taking LCM)

= 25 - 3/30

=22/30

=11/15 yards

LCM= 2*3*5= 30

Factors of 6= 2*3

Factors of 10= 2*5

7 0

3 years ago

A product is made up of components A, B, C, D, E, F, G, H, I, and J. Components A, B, C, and F have a 1/10,000 chance of failure

Svetach [21]

Answer:

The overall reliability is 99.7402 %

Step-by-step explanation:

The overall reliability of the product is calculated as the product of the working probability of the components.

For components A,B,C and F we have :

$P(failure)=\frac{1}{10000}$

⇒

$P(Work)=1-\frac{1}{10000}=\frac{9999}{10000}=0.9999$

For components D,E,G and H we have :

$P(failure)=\frac{3}{10000}$

⇒

$P(Work)=1-\frac{3}{10000}=\frac{9997}{10000}=0.9997$

Finally, for components I and J :

$P(failure)=\frac{5}{10000}$

⇒

$P(Work)=1-\frac{5}{10000}=\frac{9995}{10000}=0.9995$

Now we multiply all the working probabilities. We mustn't forget that we have got ten components in this case :

Components A,B,C and F with a working probability of 0.9999

Components D,E,G and H with a working probability of 0.9997

Components I and J with a working probability of 0.9995

Overall reliability = $(0.9999)^{4}(0.9997)^{4}(0.9995)^{2}=0.997402$

0.997402 = 99.7402 %

6 0

3 years ago

Please help me with the following questions. Thanks in advance!!

puteri [66]

Answer:

Step-by-step explanation:

In choices a and b, the bases are positive numbers greater than 1, and so these are growth functions. In c and d, the bases are between 0 and 1, and thus these are decay functions.

In the second problem we have 3ln(x + 1). Rewrite this as ln(x + 1)^3.

We also have 9ln(x - 4). Rewrite this as ln(x - 4)^9.

Because of the + sign connecting ln(x + 1)^3 and ln(x - 4)^9, these two logs combine to form

ln [ (x + 1)^3 ] * (x - 4)^9 (the log of a product).

Now we have:

ln [ (x + 1)^3 ] * (x - 4)^9 - 4ln(x + 7), or:

[ (x + 1)^3 ] * (x - 4)^9

ln ------------------------------------

(x + 7)^9

7 0

3 years ago

Read 2 more answers

Seth traveled 1 mile in 57.1 seconds. About how fast does Seth travel I. Miles per hour?

enyata [817]

57.1 seconds = 57.1 seconds * $\frac{1minute}{60seconds} * \frac{1hour}{60minutes}$ = 0.01057 hour
1 mile / 57.1 seconds = 1 mile / 0.01057 hour = 94.57 miles/hour

4 0

4 years ago