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3 years ago

A point on the line y=3x-4 has an x- coordinate of 50. what is the y-coordinate of this point

2 answers:

8 0

In order to calculate y-coordinate, just substitute the value of x-coordinate into the expression:
y = 3x - 4
y = 3(50) - 4
y = 150 - 4
y = 146

In short, Your Answer would be 146

Hope this helps!

mel-nik [20]3 years ago

3 0

The y-coordinate of the point is 146

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If x-y=√3, x²-y²=√5 & a²-a√3+1=0, then find out the value of x+y

Lemur [1.5K]

Answer:

√15/3

Step-by-step explanation:

x² - y² =√5

(x +y)*(x -y) = √5

(x +y) * √3 = √5

x+y = √5 / √3

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x +y = √15/3

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3 years ago

What is the correct answer?

Tasya [4]

Given:

The function is

$f(x)=(x+3)^2(x-5)^6$

To find:

The zeros of the given function.

Solution:

The general form of polynomial is

$P(x)=a(x-c_1)^{m_1}(x-c_2)^{m_2}...(x-c_n)^{m_n}$ ...(i)

where, a is a constant, $c_1,c_2,...,c_n$ are zeros of respective multiplicities $m_1,m_2,...,m_n$ .

We have,

$f(x)=(x+3)^2(x-5)^6$

On comparing this with (i), we get

$c_1=-3,m_1=2$

$c_2=5,m_2=6$

It means, -3 is a zero with multiplicity 2 and 5 is a zero with multiplicity 6.

Therefore, the correct option is B.

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Answer:

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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