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lutik1710 [3]
3 years ago
9

What is the slope of the line that passes through the points (-5, 4) and (15,-4)?

Mathematics
1 answer:
quester [9]3 years ago
8 0
I think it might be d?
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Which of the following statements is true? A. A tangent is never a secant. B. A secant is always a chord. C. A chord is always a
kvasek [131]
The answer to this is B.
3 0
3 years ago
The function y=60+25sin(pi/6)t, where t is in months and t=0 corresponds to April 15, models the average high temperature in deg
BartSMP [9]

Answer:

The maximum temperature will be of 85 degrees, on July 15.

Step-by-step explanation:

Sine function:

The sine function oscilates between -1 and 1, and it's maximum value is:

\sin{(\frac{\pi}{2})} = 1

y=60+25sin(pi/6)t

The maximum value will occur when \sin{(\frac{\pi t}{6}}) = 1, and it will be of 60 + 25 = 85 degrees.

When will it occur?

First we find the value of t for which the value inside the function sine is \frac{\pi}{2}. So

\frac{\pi t}{6} = \frac{\pi}{2}

\frac{t}{6} = \frac{1}{2}

2t = 6

t = \frac{6}{2} = 3

That is the number of months after April 15, which is 3 months. So July 15.

8 0
3 years ago
Plz help I will give brainliest<br> What is the value of x in this problem<br> 97x+14=13.8
sammy [17]
X= -1/485 (-0.00206)
8 0
2 years ago
AB, CD, and EF intersect at O. If CD is perpendicular to EF and m
REY [17]

Answer:

m(∠AOF) = 148°

Step-by-step explanation:

From the figure attached,

CD intersects line EF at a point O.

Line CD is perpendicular to the line EF.

m(∠AOE) = 32°

m(∠COE) = 90°

Since m(∠COE) = m(∠AOE) + m(∠AOC) = 90°

32° + m(∠AOC) = 90°

m(∠AOC) = 90° - 32° = 58°

m(∠AOF) = m(∠AOC) + m(∠COF)

               = 58° + 90°

               = 148°

Therefore, m(∠AOF) = 148° will be the answer.

4 0
3 years ago
Liam rode his bike to the store every day. It took him 45 minutes to get to school and 45 minutes to get home. If he rode for 3
Elza [17]

Answer:

1,890 minuts

Step-by-step explanation:

3 weeks = 7 days x 3 = 21 days

He rides his bike for "45 minutes to get to school and 45 minutes to get home" which is 90 minutes per day.

Therefore, in total, he rode for 21 days x 90 minutes per day = 1,890 minutes

5 0
3 years ago
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